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MakcuM [25]
3 years ago
11

A phone company offers two monthly plans. Plan A costs $13 plus an additional $0.14 for each minute of calls. Plan B costs $24 p

lus an additional $0.10 for each minute of calls.
For what amount of calling do the two plans cost the same? Minutes

What is the cost when the two plans cost the same? $
Mathematics
1 answer:
Semmy [17]3 years ago
5 0

Answer:

m = number of minutes calls

Plan A : 30 + 0.15 m

Plan B: 16 + 0.20 m

For what amount of calling do the two plans cost the same?

30 + 0.15m = 16 + 0.20m

0.05m = 14

m = 280

280 minutes of calling, the two plans cost the same

What is the cost when the two plans cost the same?

Plan A: 30 + 0.15 m = 30 + 0.15 (280)  = 72

Plan B: 16 + 0.20 m = 16 + 0.20 (280) = 72

It's cost $72 when the two plans cost the same

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Triss [41]

Answer:

5

Step-by-step explanation:

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Which integers are closest to 41
Jobisdone [24]

Answer:

the answer is 40

Step-by-step explanation:

because when you estimate 1 it will give you zero for example from 1234=0 56789 =1 so 1=to zero so the answer is 40

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Suppose the probability of selling a car today is 0.28. Find the odds against selling a car today.
Nat2105 [25]

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Step-by-step explanation:

100% - .28 = 99.78

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3 years ago
Researchers doing a study comparing time spent on social media and time spent on studying randomly sampled 200 students at a maj
Charra [1.4K]

Answer:

d. 0.0023

Step-by-step explanation:

Calculation for the probability of getting a sample average of 1.8 or less

Using this formula

z score =(X-mean)/Standard errror

Where,

Standard error =Standard deviation/√(n)

Let plug in the formula

P(Xbar<1.8)=P(Z<(1.8 hours per day -2.2 hours per day)/(2 hours /√(200))

P(Xbar<1.8)=P(Z<-0.4/(2/14.14))

=P(Z<-0.4/0.1414)

=P(Z<-2.83)

Now let find the Z score of P(Z<-2.83) using the z table

P=0.0023

Therefore the probability of getting a sample average of 1.8 or less is:0.0023

5 0
3 years ago
Suppose the population standard deviation is σ = 5 , an SRS of n = 100 is obtained, and the confidence level is chosen to be 98%
beks73 [17]

Answer:

1.165.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.98}{2} = 0.01

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.01 = 0.99, so z = 2.33

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this problem, we have that:

\sigma = 5, n = 100. So

M = z*\frac{\sigma}{\sqrt{n}}

M = 2.33*\frac{5}{\sqrt{100}} = 1.165

So the correct answer is:

1.165.

6 0
3 years ago
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