The answer is probably the third one or last
<span><span>DO use multiplication sign '*' (the STAR) symbol. For the simplifier, xy is NOT the same as x*y or yx. Simplifier thinks that xy is a separate variable. Good example: x*y-y*(x+2). Bad example: xy-y(x+2).</span>DO use '*' when multiplying a variable by an expression in parentheses: x*(x+2). Otherwise, my simplifier will think that you are trying to use a function and will become confused.Use parentheses liberally to avoid any ambiguity. (x+y)/(x-y) is NOT the same as x+y/x-y. x+y/x-y means x+(y/x)-y.</span>Operations<span>Use '*' (STAR) for multiplication. 2*3 is legal, 2x3 will be misunderstood.Use '^' (CARET) for power. 2^3 means 2 to degree of 3, or 8.Use '/' (FORWARD SLASH) for divisionOnly '(' and ')' (parentheses) are allowed for grouping terms. Curly or square brackets are used for other purposes.</span>
Operation priority: + and - have lowest priority, * and / h
Good Examplesx*y-x*(y+2) <-- '*' is used for multiplications
a^b*3 <-- means (a to the degree of b) multiplied by 3
Bad examples<span>xy-yx <-- variable xy and variable yx are different variables
y(x-2) <-- simplifier will think that it is function y of x-2.</span>
Answer:
2H2S (g) + 3O2 (g) → 2H2O (l) + 2SO2 (g)
Calculate ΔH° from the given data. Is the reaction exothermic or endothermic?
ΔH°f (H2S) = -20.15 kJ/mol; ΔH°f (O2) = 0 kJ/, mol; ΔH°f (H2O) = -285.8 kJ/mol; ΔH°f (SO2) = -296.4 kJ/mol
Answer:
8
Step-by-step explanation:
hope i helped have a verey good day
