Answer:
There are 15 combinations.
Step-by-step explanation:
A restaurant is offering a dinner special that includes one starter and one entree.
Starter: bread-sticks, soup, salad
Entree: beef, fish, chicken, shrimp, pork
So, we have 3 starters and 5 entrees.
To know the possible dinner special combinations we will simply multiply the two.
Therefore, there are 15 combinations.
The slop would be 1/6.
you put it into slope intercept form (y=mx+b). parallel lines always have the same slope.
The answer is :23
B:34
C:56
C. x³-4x²-16x+24.
In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.
Multiply the polynomials (x-6)(x²+2x-4)
Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:
(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)
x³+2x²-4x -6x²-12x+24
Ordering the similar monomials:
x³+(2x²-6x²)+(-4x - 12x)+24
Getting as result:
x³-4x²-16x+24
