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MatroZZZ [7]
3 years ago
15

What's the difference between 1261⁄4 and 78 2⁄3? 

Mathematics
2 answers:
lubasha [3.4K]3 years ago
4 0
126 1/4 - 78 2/3 =
505/4 - 236/3 =
1515/12 - 944/12 =
571/12 =
47 7/12 <==
Alisiya [41]3 years ago
4 0

Answer: The answer is (B) 47\dfrac{7}{12}.

Step-by-step explanation:  We are given to find the difference between the following two numbers:

n_1=126\dfrac{1}{4},~~~n_2=78\dfrac{2}{3}.

To find the difference, we need to subtract the smaller number from the larger one.

Since, n_1>n_2, so the difference is given by

d\\\\=n_1-n_2\\\\=126\dfrac{1}{4}-78\dfrac{2}{3}\\\\=\dfrac{505}{4}-\dfrac{236}{3}\\\\=\dfrac{505\times3-236\times4}{12}\\\\=\dfrac{1515-944}{12}\\\\=\dfrac{571}{12}\\\\=47\dfrac{7}{12}.

Thus, (B) 47\dfrac{7}{12} is the correct option.

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There are 24 girls on the track team. First race2/3 girl ran.only1/4 girl ran in second race. 1/6 on third race. Hiw many more g
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Answer:

10 more girls

Step-by-step explanation:

So here 2/3 of 24 ran for first race

Then it gives us that 16 girls ran for first race.

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5 0
3 years ago
Write the quadratic function f(x) = x2 - 5x + 3 in vertex form. Complete the square to determine the maximum or minimum value of
enyata [817]

Answer:

a). Vertex form f the function f(x) = (x - 2.5)²+3.25

b). Maximum value of the function is (-3)

Step-by-step explanation:

a). f(x) = x² - 5x + 3

we have to write this function in the vertex form.

f(x) = x² - 2(2.5)x + 3

    = [(1)²x²- 2(2.5)x + (2.5)²-(2.5)²] + 3

    = (x - 2.5)²- 6.25 + 3

    = (x - 2.5)² - 3.25

So the vertex for of the function is

f(x) = (x - 2.5)² - 3.25

b). Given quadratic function f(x) = -x² - 6x + 6 is in the standard form of f(x) = ax² + bx + c.

By comparing the coefficients of both the functions,

a = -1, b = 6 and c = 6

Here the value of a is negative, therefore, the given parabola is opening downwards.

And the maximum will occur at

x=-\frac{b}{2a}

When we plug in the values,

x=-\frac{6}{2(-1)}

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Now to get the value of maximum of the function we will get the value of f(3).

f(3) = -(3)²- 6(3) + 6

f(3) = 9 - 18 + 6

f(3) = -3

Therefore, maximum value of the quadratic function is (-3).

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3 years ago
Use the zeros of the following quadratic to find the x-value of the vertex.
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B I got this by graphing it into my graphing calculator. Hope this helps
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Given s(x) = 2x - 3 and t(x) = 5x + 4. find the formula and domain for s(x) over t(x) and w(x) = t(x) over s(x)
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