Answer:
B. x
Step-by-step explanation:
The answer would be graph x. A function must be that one x value should only have one y value. graph w doesn't work since when you plug in 0, you get two y's. same thing with z. Y doesn't work since at x value of 3, it curves back so x value 2 has 2 y's. X is the only one that each x value has only one y.
positive divisors of 10: 1,2,5,10

I know the 1st and last one but i’m not sure on the rest sorry :(
Answer: -9 = a(1 - 3)² + 3
Step-by-step explanation:
Vertex Form Equation:
y = a(x - h)² + k
vertex: (h, k) which means
h = 3
k = 3
because your vertex is (3, 3).
Your point is (1, -9) which is (x, y).
This means
x = 1
y = -9
Now, plug everything into your Vertex Form Equation:
-9 = a(1 - 3)² + 3
That’s your equation and final answer, but of course, if you need to, you can solve for a if you need to.
If a is positive, the parabola opens up. If a is negative, the parabola opens down.
Hope this helps!
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.

Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

Indeed, those two numbers are relatively prime.