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3 years ago

What is the surface area of 4ft 17ft and 14ft

Mathematics

1 answer:

amm18123 years ago

3 0

I beat my d on the daily ayy

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Pleaseeeee helpppp please

Whitepunk [10]

Answer: I dont know i am only 9 years old i will call the internet police

Step-by-step explanation:

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3 years ago

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Heedayati drives for 180 km from Town P to Town Q. The average speed of Heedayati is 60 km/h. Heedayati took 45 minutes less for

Nadusha1986 [10]

Answer:

180 divided by 45 is equal to 4km/h

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3 years ago

Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB

Digiron [165]

Answer: The distace between midpoints of AP and QB is $\frac{a}{8}$ .

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = $\frac{AP}{2}$

QB = $\frac{AP}{2}$

Substituing:

AP + 2*( $\frac{AP}{2}$ ) = a

2AP = a

AP = $\frac{a}{2}$

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = $\frac{AP}{2}$

QB = $\frac{a}{2}*\frac{1}{2}$

QB = $\frac{a}{4}$

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

$\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}$

$\frac{AP}{2} = \frac{a}{4}$

<u>Midpoint of QB</u>:

$\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}$

$\frac{QB}{2} = \frac{a}{8}$

The distance is:

d = $\frac{a}{4} - \frac{a}{8}$

d = $\frac{a}{8}$

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3 years ago

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s t)(-7)? A. -439 B. -141 C. 153 D. 443

Ulleksa [173]

Answer: Option A -439

(s o t)(x)=s(t(x))
(s o t)(-7)=s(t(-7))
x=-7→t(-7)=3(-7)→t(-7)=-21
(s o t)(-7)=s(t(-7))=s(-21)
x=-21→s(-21)=2-(-21)^2=2-441→s(-21)=-439
(s o t)(-7)=s(t(-7))=s(-21)=-439
Answer: Option A -439

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2 years ago

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Will give Brainliest and Five Stars to the correct answer

nadezda [96]

The correct answer is y = 1/8x^2

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