The absolute difference between the greatest and the least of these three numbers in the arithmetic sequence is 10.
The sequence is an arithmetic sequence. Therefore,
d = common difference
let
a = centre term
Therefore, the 3 consecutive term will be as follows
a - d, a, a + d
a - d + a + a + d = 27
3a = 27
a = 27 / 3
a = 9
Therefore,
(a-d)² + (a)² + (a + d)² = 293
(a²-2ad+d²) + 9² + (a² + 2ad + d²) = 293
(81 - 18d + d²) + 81 + (81 + 18d + d²) = 293
243 + 2d² = 293
2d² = 50
d² = 50 / 2
d = √25
d = 5
common difference = 5
Therefore, the 3 numbers are as follows
9 - 5 , 9, 9 + 5 = 4, 9, 14
The difference between the greatest and the least of these 3 numbers are as follows:
14 - 4 = 10
learn more on Arithmetic progression: brainly.com/question/25749583?referrer=searchResults
Answer:3 & 4
Step-by-step explanation: those are the two with multiplication/division
A negative number divided by positive is a negative quotient and vice versa.
So
5.7 / -2.2
-0.01 / 0.05
Are the ones with negative quotients
That's not true because the GCF of 9 and 12 are both three and three is an odd number
Answer:
a) 952
b) 136
Step-by-step explanation:
<u>Ratio of b:g = 3:4, based on this we have:</u>
- Number of boys = 3x
- Number of girls = 4x
- Total number of pupils = 3x+4x = 7x
<u>Number of spectacle wearers:</u>
- 1/3*3x + 3/8*4x = x + 3/2x = 2.5x
<u>Number of those not wearing spectacles:</u>
<u>And this number equals to 612, then we can find the value of x:</u>
- 4.5 x = 612
- x= 612/4.5
- x= 136
a) T<u>otal number of pupils:</u>
b)<u> The difference in the number of boys and girls:</u>
