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o-na [289]
3 years ago
11

In a hydroelectricity production, water falls from a dam into a turbine wheel 49 m below. What is the velocity of water at the t

urbine?
A) 0 m/s
B) 15.5 m/s
C) 31 m/s
D) 46.5 m/s
Mathematics
1 answer:
ozzi3 years ago
7 0

Answer:

C: 31 m/s

Step-by-step explanation:

It falls from a dam.

Thus;

Initial velocity; u = 0 m/s

Height; h = 49 m

Acceleration due to gravity is 9.8 m/s²

To solve for the final velocity this, we will use Newton's third equation of motion;

v² = u² + 2gh

v² = 0² + 2(9.8 × 49)

v = √960.5

v ≈ 31 m/s

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Answer:

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And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example\alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

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Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Where \mu_1 and \mu_2 represent the percentages that we want to test on this case.

The statistic calculated is on this case was Z=4.21. Since we are conducting a two tailed test the p value can be founded on this way.

p_v =2*P(Z>4.21) =2.55x10^{-5}

And we can use the following excel code to find it:"=2*(1-NORM.DIST(4.21,0,1,TRUE)) "

With the p value obtained and using the significance level assumed for example\alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the percentage 1 is significantly different from the percentage 2.

And the best option on this case would be:

 D) Are statistically different.

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Part A: The decimal form of the rational number 3/40 is
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\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c | }  \\ \bf{Part  \: A} & \bf \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}} \\  \\   \hline \\  \bf{Part  \: B}& \:  \bf \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3    \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  } \\  \\ \hline \\ { \bf Part  \:C \: }&  \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. \:  \:  \:  \:  \:  \:  \:  \:  }}    \\  \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}

\bf \underline{Answer-} \\

{ \bf{Part  \: A \:  | \:  \footnotesize{The \:  decimal \:  form  \: of \:  the \:  rational \:  number \:  \dfrac{3}{40} \: is \: \gray{ \normalsize{ 0.075 }}}}}

{ \bf{Part  \: B \:  | \:  \footnotesize{The \: value \: of \:  \dfrac{1}{ \sqrt[4]{(9)^{ - 2} } } \: is \: \normalsize 3   }}}

\bf \underline{Step \:by \:step\: Explanation-} \\

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[4]{(9)^{ - 2} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt[ \cancel4]{(9)^{ \cancel{ - 2}} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{ \sqrt{9^{  - 1} } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{  {3}^{ - 1  } }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies\dfrac{1}{   \dfrac{1}{3}  }}

{ \sf  \:  \:  \:  \:  \:   :  \:  \:  \implies3}

{ \bf Part  \:C \: } | \:  { \bf\footnotesize{On \:  simplifying  \:  \: (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7}) \: we \: get \: \normalsize{ 17 }. }}

{~~~\sf ~~:~~\implies (5+3 \sqrt{7} ) + (12 - 3 \sqrt{7})}

{~~~~\sf ~:~~\implies 5+ \cancel{3 \sqrt{7}} + 12 \cancel{ - 3 \sqrt{7}}}

{~\sf ~~~~:~~\implies 17}

\underline{\rule{200pt}{2.5pt}}

8 0
2 years ago
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