Question

Find the indicated limit, if it exists. limit of f of x as x approaches negative 1 where f of x equals 4 minus x when x is less than negative 1, 5 when x equals negative 1, and x plus 6 when x is greater than negative 1 6 0 5 The limit does not exist.

Answer 1

Answer:

The limit is 5

Step-by-step explanation:

A limit exists if the one-sided limits are equal. So we analyze the limit by approaching it from both the left and the right.

From the left: $\lim_{x \to \--1} F(x) = \lim_{x \to \--1} (4-x) = 4-(-1) = 5$

From the right: $\lim_{x \to \--1} F(x) = \lim_{x \to \--1} (x+6) = -1+6 = 5$

At x= -1 itself: F(x) = 5

Since the limits when approaching from the left and right match, the limit does exist. Thus we conclude that the limit of f of x as x approaches negative 1 is five.