Given that the probability of the area under the standard normal curve is 0.03593.
The z-score will be resolved using the z-score table.
Using the z-score table, the value of the z-score of 0.03593 to the left is -1.8.
Hence, the answer is -1.8.
Answer:
2 & 4
1 & 3
5 & 7
8 & 6
Vertical angles are formed in a set of intersecting lines. They are two differrent angles that are opposite of eachother but have the same angle.
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Answer:</h2><h2>The third one</h2><h2>
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Hope this helps!! ♥︎</h2>
Explanation:
<h3>S + T = R</h3>
Suppose we define ...
a(x) = 2x, for 0 ≤ x ≤ 1
b(x) = x^2, for 0 ≤ x ≤ 1
Then we have the following:
c(x) = a(x) +b(x) = 2x +x^2, for 0 ≤ x ≤ 1
S = max(a(x)) = a(1) = 2
T = max(b(x)) = b(1) = 1
R = max(c(x)) = c(1) = 2 +1 = 3
This value of R satisfies S + T = R.
We note that for x=p=1, we have S = a(p), T = b(p), and R = c(p). The first attachment illustrates this case.
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<h3>S + T ≠ R</h3>
Suppose we define ...
a(x) = x, for 0 ≤ x ≤ 1
b(x) = 1 -x^2, for 0 ≤ x ≤ 1
c(x) = a(x) +b(x) = x + 1 -x^2, for 0 ≤ x ≤ 1
Then we have the following:
S = max(a(x)) = a(1) = 1
T = max(b(x)) = b(0) = 1
R = max(c(x)) = c(0.5) = 1.25 ≠ 1 + 1 = 2
This value of R does not satisfy S + T = R.
We note that for p, q, r we have S = a(p), T = b(q), R = c(r) and p≠q≠r. The second attachment illustrates this case.
Answer:
The park is <u>31 inches</u> wide in the drawing.
Step-by-step explanation:
Given:
Vicky drew a scale drawing of a city. She used the scale 1 inch : 2 yards.
The actual width of a neighborhood park is 62 yards.
Now, to find the width of park in drawing.
Let the width of park in drawing be 
The scale drawing of the city is 1 inch : 2 yards.
So, 1 inch is equivalent to 2 yards.
Thus,
is equivalent to 62 yards.
Now, to get the width of park in drawing by using cross multiplication method:

By cross multiplying we get:

Dividing both sides by 2 we get:


Therefore, the park is 31 inches wide in the drawing.