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The arcs intersected by these chords are not congruent.
Given that two circles with different radii have chords AB and CD, such that AB is congruent to CD.
Let r₁ and r₂ be the radii of two different circles with centers O and O' respectively.
Assuming that the each of the ∠АОВ and ∠CO'D is less than or equal to π.
Then, we have isosceles triangle AOB and CO'D such that,
AO = OB = r₁,
CO' = O'D = r₂,
Let us assume that r₁< r₂;
We can see that arc(AB) intersected by AB is greater than arc(CD), intersected by the chord CD;
arc(AB) > arc(CD) .......(1)
Indeed,
arc(AB) = r₁ angle (AOB)
arc(CD) = r₂ angle (CO'D)
So, we have to prove that ;
∠AOB >∠CO'D ......(2)
Since each angle is less than or equal to π, and so
∠AOB/2 and ∠CO'D/2 is less than or equal to π
it suffices to show that :
tan(AOB/2) >tan(CO'D/2) ......(3)
From triangle AOB :
tan(AOB/2) = AB/(2*r₁)
tan(CO'D/2) = CD/(2*r₂)
Since AB = CD and r₁ < r₂ (As obtained from the result of (3) ), therefore, arc(AB) > arc(CD).
Hence, for two circles with different radii have chords AB and CD, such that AB is congruent to CD but the arcs intersected by these chords are not congruent.
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Answer:
Un batido de proteínas cuesta $ 5,25.
Step-by-step explanation:
El sistema de ecuaciones descrito al final del enunciado coincide con lo descrito al comienzo del mismo, de modo que podemos concentraron casi exclusivamente en la resolución del sistema en cuestión, la cual se describe a continuación:
Este es el sistema a resolver:
(1)
(2)
Donde es el coste de un batido de fresa y
corresponde al coste de un batido de proteínas:
1) Despejamos en (1):
2) Eliminamos en (2):
3) Simplificamos y despejamos :
Un batido de proteínas cuesta $ 5,25.