P(1) = P(0) [exp (rt)]
9,800 = 10,000 (0.98)^1
r = loge<span> (0.98) = ln (0.98) = -0.0202
</span>
<span>P(t) = P(0)[exp(-0.0202t)]</span>
-7+(9)=2
you can do the opposite of what is given (9-7)
Answer:
36. Limit = 2/3.
Step-by-step explanation:
36.
(∛ x- 1) / (√x - 1)
Rationalise the expression:-
Multiply top and bottom by (√x + 1):-
(∛x - 1)(√x + 1) / (√x - 1)(√x + 1)
= x^5/6 + ∛x - √x - 1 / (x - 1)
Applying L'hopital's rule ( differentiating top and bottom of the fraction) we have:
Limit as x ----> 1 of [5/6 x^-1/6 + 1/3 x^(-2/3) - 1/2x^-1/2] / 1
= 5/6(1) + 1/3(1) - 1/2(1) = 2/3 (answer).
Answer:
i. x and a are increasing while y and b are reducing
Answer:
C. Yes Devon should have evaluated f(3).
Step-by-step explanation:
She substituted the wrong value. For x - 3 to be a factor f(3) must equal 0.
f(3) = 3^3 + 3^2 - 10(3) + 8 = 27 + 9 - 30 + 8
= 14, so x- 3 is not a factor anyway but she did substitute the wrong value.
