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Elena-2011 [213]
3 years ago
10

Manny is paid weekly. His weekly salary is $939. What is his annual salary?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
5 0

Answer:

134.142857143

Step-by-step explanation:

this is the answers

boyakko [2]3 years ago
4 0

Answer:

48828

Step-by-step explanation:

939×52 (52 weeks in a year)

=48828

not sure about this answer

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HELP ME PLEASE I NEED HELP
anyanavicka [17]

Answer:

Step-by-step explanation:

This is a narrower-than-normal absolute value graph, which is a v-shaped graph. It's pointy part, the vertex, lies at (2, -3) and it opens upwards without bounds along both the positive and negative x axes. Therefore, as x approaches negative infinity, f(x) or y (same thing) approaches positive infinity. As x approaches positive infinity, f(x) approaches positive infinity.

6 0
3 years ago
What's the sum of 5 feet 9 inches in 12 ft and 3 in
galben [10]
First convert everything into inches.

1 foot = 12 in
5 feet = 5*12 = 60 in
12 feet = 12*12 = 144 in

Now add them together

60 + 9 + 144 + 3 = 216 in

or

18 feet

Hope this helps :)
4 0
2 years ago
3x-18 &gt;3 <br> need to solve for X
KATRIN_1 [288]

Answer:

x > 7

Step-by-step explanation:

3x-18 > 3

+18 3x-18 > 3 +18

3x > 21

x > 7

5 0
2 years ago
Read 2 more answers
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
Please help 7x1990x19x43
RideAnS [48]

Answer:

11380810

Step-by-step explanation:

hope this helps

8 0
2 years ago
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