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8090 [49]
2 years ago
6

Determine whether the graph represents a proportional relationship.

Mathematics
1 answer:
Alexus [3.1K]2 years ago
4 0

Answer:

No, it is not a proportional relationship because the graph does not go through the origin

Step-by-step explanation:

it has to go through zero as in the (origin)

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Answer:

Sampling is necessary because researchers in the social sciences almost never have enough resources — time or money — to collect information about the entire set of subjects of interest to them.

Step-by-step explanation:

Sampling is done because you usually cannot gather data from the entire population. Even in relatively small populations, the data may be needed urgently, and including everyone in the population in your data collection may take too long.

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Factor completely 2X^3-2x-40
Sholpan [36]
2X^3-2x-40=0
Hope this helps
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Which of the points are solutions to the inequality? Check all that apply. (–3, 3) (–2, –2) (–1, 1) (0, 1) (2, 5)
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Answer:

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Step-by-step explanation:

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2 years ago
Please help asap 30 pts
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5 0
3 years ago
B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, find the measure of Ab.
LuckyWell [14K]

__________________________

Measurement of "AC" :

(x + 5) + (2x <span>− 11) ;
________________________

Find the measurement of "AB" [which is: "(x+5)" ]: 
______________________________________________
First, simplify to find the measurement of "AC" :
________________________________________
 </span>(x + 5) + (2x − 11) ;

=  (x + 5) + 1(2x − 11) ;

=   x + 5 + 2x − 11 ;

 → Combine the "like terms" ; 

   x + 2x = 3x ;
   
   5 − 11 = - 6 ;
______________
to get:  3x − 6 ; 
_______________
So,  (x + 5) + (2x − 11) =  3x − 6 ;
_______________________________
Solve for:  "(x + 5)"
_______________________________

We have: 
_______________________________

(x + 5) + (2x − 11) =  3x − 6  ;

Subtract:  "(2x − 11)" ;  from EACH SIDE of the equation ;
                                      to isolate "(x + 5)" on one side of the equation; 
                                      and to solve for "(x + 5)" ;
________________________________________________________
    →  (x + 5) + (2x − 11) − (2x − 11) =  (3x − 6) − (2x − 11) ;
  
         → (x + 5)  = (3x − 6) − (2x − 11) ;
_________________________________________________
  Note:  Simplify:  "(3x − 6) − (2x − 11)" ;

     →  (3x − 6) − (2x − 11)  ;
 
         =  (3x − 6) − 1(2x − 11) ;
 
         =   3x − 6 − 2x + 11 ;
__________________________
   →  Combine the "like terms" :
_____________________________
         +3x − 2x = 1x = x ;
  
          -6 + 11 = 5 ; 
_____________________________
To get:  x + 5 ; 

So we have:
______________________________
 x + 5 = x + 5 ; 
______________________________

So, x = all real numbers.

x = <span>ℝ </span>
4 0
3 years ago
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