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2 years ago

Determine whether the graph represents a proportional relationship.

Mathematics

1 answer:

Alexus [3.1K]2 years ago

4 0

Answer:

No, it is not a proportional relationship because the graph does not go through the origin

Step-by-step explanation:

it has to go through zero as in the (origin)

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What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S = 40° ∠P = 160°; ∠S = 20°

strojnjashka [21]

*see attachement for diagram

Answer:

∠P = 140°; ∠S = 40°

Step-by-step explanation:

The figure given is a parallelogram.

Consecutive angles (adjacent angles) of a parallelogram are supplementary.

Therefore:

(x + 15)° + (6x - 10)° = 180°

Solve for x

x + 15 + 6x - 10 = 180

Add like terms

7x + 5 = 180

7x = 180 - 5

7x = 175

x = 175/7

x = 25

✔️m<P = m<R = 6x - 10 (opposite angles of a parallelogram are congruent)

m<P = 6x - 10

Plug in the value of x

m<P = 6(25) - 10 = 140°

✔️m<S = m<Q = x + 15 (opposite angles of a parallelogram are congruent)

m<S = x + 15 = 25 + 15 = 40°

5 0

2 years ago

Find the sine of Write your answer in simplified, rationalized form. Do not round. Please help!!!!!

erma4kov [3.2K]

Answer:

Sin (E) = √74/(2√23)

Step-by-step explanation:

Reference Angle = E

Hypotenuse = 2√23

Adjacent = 3√2

Opposite = DC = √(2√23)² - (3√2)²) = √(4*23 - 9*2) = √(92 - 18) = √74 (pythagorean theorem)

Recall SOHCAHTOA.

Thus,

Sin (E) = opp/hyp

Sin (E) = √74/(2√23)

6 0

2 years ago

Rewrite log; x = 4 in exponential form.

aliya0001 [1]

Answer:

Step-by-step explanation

(B) x=34

7 0

3 years ago

Which equation is y = –6x^2 + 3x + 2 rewritten in vertex form? y = negative 6 (x minus 1) squared + 8 y = negative 6 (x + one-fo

mart [117]

Answer:

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

Step-by-step explanation:

Given:

$y = -6x^2 + 3x + 2$

Required

Rewrite in vertex form

The vertex form of an equation is in form of: $y = a(x - h)^2+ k$

Solving: $y = -6x^2 + 3x + 2$

Subtract 2 from both sides

$y - 2 = -6x^2 + 3x + 2 - 2$

$y - 2 = -6x^2 + 3x$

Factorize expression on the right hand side by dividing through by the coefficient of x²

$y - 2 = -6(x^2 + \frac{3x}{-6})$

$y - 2 = -6(x^2 - \frac{3x}{6})$

$y - 2 = -6(x^2 - \frac{x}{2})$

Get a perfect square of coefficient of x; then add to both sides

------------------------------------------------------------------------------------

Rough work

The coefficient of x is $\frac{-1}{2}$

It's square is $(\frac{-1}{2})^2 = \frac{1}{4}$

Adding inside the bracket of $-6(x^2 - \frac{x}{2})$ to give: $-6(x^2 - \frac{x}{2} + \frac{1}{4})$

To balance the equation, the same expression must be added to the other side of the equation;

Equivalent expression is: $-6(\frac{1}{4})$

------------------------------------------------------------------------------------

The expression becomes

$y - 2 -6(\frac{1}{4})= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{6}{4}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

$y - 2 -\frac{3}{2}= -6(x^2 - \frac{x}{2} + \frac{1}{4})$

Factorize the expression on the right hand side

$y - 2 -\frac{3}{2}= -6(x - \frac{1}{2})^2$

$y - (2 +\frac{3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{4+3}{2})= -6(x - \frac{1}{2})^2$

$y - (\frac{7}{2})= -6(x - \frac{1}{2})^2$

$y +\frac{7}{2} = -6(x - \frac{1}{2})^2$

Make y the subject of formula

$y = -6(x - \frac{1}{2})^2 -\frac{7}{2}$

Solved

7 0

3 years ago

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What is 1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1x1

Reptile [31]

Answer:

Step-by-step explanation:

Because each is just being multiplied by the same number.

7 0

3 years ago

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