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Andrew [12]
3 years ago
9

Mitchell works at a concession stand selling hotdogs and cans of soda. A hotdog costs $3.00 and a can of soda costs $1.00. One n

ight, he notices that he sold a total of 350 items and collected a total of $624.
Mathematics
1 answer:
Dimas [21]3 years ago
8 0
If you are asking how many hot dogs and cans of soda are sold, this is how I solved it.

Given:
cost of hot dog $3 
cost of a can of soda $1
total items sold: 350
total sales: $624

let h stand for hot dog and s stand for soda.

h + s = 350

3h + 1s = 624

h = 350 - s
3(350-s) + s = 624
1,050 -3s + s = 624
-2s = 624 - 1050
-2s = -426
-2s/-2 = -426/-2
s = 213   cans of soda

h = 350 - s
h = 350 - 213
h = 137 hot dogs

3h + s = 624
3(137) + 213 = 624
411 + 213 = 624
624 = 624

Mitchell sold 137 hot dogs and 213 cans of soda.
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Answer:

No solution

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Step-by-step explanation:

Given: The system of inequality

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y

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Option 1: (-5,2)

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Equation 1                               Equation 2

2>\dfrac{3}{2}(-5)-1                            2

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Option 2: (2,2)

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Equation 1                              Equation 2

2>\dfrac{3}{2}(2)-1                    2

2>2                                           2

  FALSE                                      FALSE

Option 3: (5,2)

Put x=-5 and y=2

Equation 1                            Equation 2

2>\dfrac{3}{2}(5)-1                      2

2>6.5                                           2

 FALSE                                      TRUE

Option 1, 2 and 3 are incorrect because both equation must be true for solution.

Hence, Option 4 is correct no solution.  

6 0
3 years ago
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