Mitchell works at a concession stand selling hotdogs and cans of soda. A hotdog costs $3.00 and a can of soda costs $1.00. One n
ight, he notices that he sold a total of 350 items and collected a total of $624.
1 answer:
If you are asking how many hot dogs and cans of soda are sold, this is how I solved it.
Given:
cost of hot dog $3
cost of a can of soda $1
total items sold: 350
total sales: $624
let h stand for hot dog and s stand for soda.
h + s = 350
3h + 1s = 624
h = 350 - s
3(350-s) + s = 624
1,050 -3s + s = 624
-2s = 624 - 1050
-2s = -426
-2s/-2 = -426/-2
s = 213 cans of soda
h = 350 - s
h = 350 - 213
h = 137 hot dogs
3h + s = 624
3(137) + 213 = 624
411 + 213 = 624
624 = 624
Mitchell sold 137 hot dogs and 213 cans of soda.
You might be interested in
Answer:21
Step-by-step explanation:i did the math
Because you can simplify 40/100 and get 4/10
when you divide 40/100 by ten on the den. and num. you will get 4/10
We have the following:
Answer:
3 pounds
Step-by-step explanation:
f(x) = 3/(x + 2) - √x - 3
f(7) = 3/(7 + 2) - √7 - 3
f(7) = 3/9 - √4
f(7) = 0.333 - 2
f(7) = -1.67