Can some one help me with this question its hard :( down below ill give brainliest
1 answer:
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We know that the law of sines states that:
For simplicity, let:
In triangle A1BC this leads to:
Therefore:
Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:
ANSWERS
(5) Graph:
(6) Solutions: (-1, -5) and (-2, -7)
Not solutions: (1, 1) and (-4, -3)
EXPLANATION
(5) To graph this system, first, we have to graph each of the inequalities. Both are linear, so we have to graph each line with a dashed line - this is because they are "less than" the line, so the line is not included, and shade the area below each of them.
The first inequality is y < -3x-4,
The second inequality is y < 2x - 1,
The graph of the system is the area shared by both graphs,
(6) Any point that is inside the shaded area is a solution of the system. For example, points (-1, -5) and (-2,-7) are solutions to the system.
On the other hand, any point outside that area, or on the dashed lines is not a solution. For example, points (1, 1) and (-4, -3) are not solutions
