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Flauer [41]
3 years ago
8

Can some one help me with this question its hard :( down below ill give brainliest

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

Answer:

The answer is letter D. XY^4/5

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Thats my question down there mates
Law Incorporation [45]

Answer:

x = 9

Step-by-step explanation:

A line segment parallel to a side of a triangle and intersecting the other 2 sides divides the 2 sides in proportion, that is

\frac{9}{72} = \frac{1}{8} = \frac{3x-20}{56} ( cross-  multiply )

8(3x - 20) = 56

24x - 160 = 56 ( add 160 to both sides )

24x = 216 ( divide both sides by 24 )

x = 9

7 0
3 years ago
Read 2 more answers
Please help will mark thank you and brainliest
Masteriza [31]

Step-by-step explanation:

it's the 3rd one because it is greater than the other angle

8 0
3 years ago
Find three different irrational numbers between the rational numbers 0.13 and 0.14
drek231 [11]
In order to solve this problem easily you coin this method: Find the squares of 0.13 and 0.14. They are respectively 0.0169 and 0.0196. Irrational numbers are going to located between this interval, considering that we are not counting perfect squares. \sqrt{0.0168} ,  \sqrt{0.017} , \sqrt{0.0175} are the three possible answers. 
4 0
3 years ago
Read 2 more answers
Complete the identity
german

Answer:

sin⁡(α+β)/sin⁡(α-β) ==(tan⁡ α+tan ⁡β)/(tan ⁡α-tan ⁡β )

Step-by-step explanation:

We have to complete

sin⁡(α+β)/sin⁡(α-β) = ?

The identities that will be used:

sin⁡(α+β)=sin⁡ α cos ⁡β+cos ⁡α sin ⁡β

and

sin⁡(α-β)=sin⁡ α cos⁡ β-cos⁡ α sin⁡ β  

Now:

=   sin⁡(α+β)/sin⁡(α-β)  

=(sin⁡ α cos⁡ β+cos ⁡α sin⁡ β)/(sin ⁡α cos ⁡β-cos ⁡α sin ⁡β)

In order to bring the equation in compact form we wil divide both numerator and denominator with  cos⁡ α cos⁡ β  

=  (((sin ⁡α cos ⁡β+cos ⁡α sin ⁡β))/(cos ⁡α cos ⁡β ))/(((sin α  cos ⁡β-cos ⁡α sin ⁡β))/(cos ⁡α  cos ⁡β))

=((sin⁡ α cos⁡β)/(cos ⁡α cos ⁡β )+(cos ⁡α sin ⁡β)/(cos ⁡α cos ⁡β ))/((sin ⁡α cos ⁡β)/(cos ⁡α  cos ⁡β )-(cos ⁡α sin ⁡β)/(cos ⁡α cos ⁡β))  

=(sin⁡ α/cos ⁡α + sin ⁡β/cos ⁡β )/(sin ⁡α/cos ⁡β - sin ⁡β/cos ⁡β)

=(tan ⁡α+tan ⁡β)/(tan ⁡α-tan ⁡β )

So,

sin⁡(α+β)/sin⁡(α-β) ==(tan⁡ α+tan ⁡β)/(tan ⁡α-tan ⁡β)

8 0
4 years ago
What are the values of a and b?
krok68 [10]

Answer:a=8; b=40

Step-by-step explanation:answer d is correct

7 0
3 years ago
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