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White raven [17]
3 years ago
6

Katie buys 4 packages of cookies for $16. In each package of cookies there are 2 cookies. How much does it cost Katie for one co

okie?
Mathematics
1 answer:
AlekseyPX3 years ago
8 0

Answer:

$2 each cookie

Step-by-step explanation:

4 divided by 16

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Help please! <3
lora16 [44]
-x/2 + 4 > = 6
-x/2 > = 6 - 4
-x/2 > = 2...multiply both sides by -2
x < = -4
_________________________________________
x + 3/2 < 7/4
x < 7/4 - 3/2
x < 7/4 - 6/4
x < 1/4
6 0
3 years ago
During the period of time that a local university takes phone-in registrations, calls come in
Zinaida [17]

Answer:

a) The expected number of calls in one hour is 30.

b) There is a 21.38% probability of three calls in five minutes.

c) There is an 8.2% probability of no calls in a five minute period.

Step-by-step explanation:

In problems that we only have the mean during a time period can be solved by the Poisson probability distribution.

Poisson probability distribution

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

a. What is the expected number of calls in one hour?

Calls come in at the rate of one each two minutes. There are 60 minutes in one hour. This means that the expected number of calls in one hour is 30.

b. What is the probability of three calls in five minutes?

Calls come in at the rate of one each two minutes. So in five minutes, 2.5 calls are expected, which means that \mu = 2.5. We want to find P(X = 3).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 3) = \frac{e^{-2.5}*(2.5)^{3}}{(3)!} = 0.2138

There is a 21.38% probability of three calls in five minutes.

c. What is the probability of no calls in a five-minute period?

This is P(X = 0) with \mu = 2.5.

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2.5}*(2.5)^{0}}{(0)!} = 0.0820

There is an 8.2% probability of no calls in a five minute period.

6 0
3 years ago
Who wants to help me with my aleks programs
gavmur [86]
I can try what exactly do you need help with
8 0
3 years ago
Please help it's due today​
sergiy2304 [10]

Answer:

9/7, 1/6, -3, 4/5

Step-by-step explanation:

Use the gradient =\frac{rise}{run} formula to solve this.

4: gradient = \frac{14-5}{8-1} = \frac{9}{7}

5: gradient = \frac{10-9}{2-(-4)} = \frac{1}{6}

6: gradient = \frac{-5-4}{6-3} = \frac{-9}{3}  = -3

7: gradient = \frac{-1-(-5)}{7-2} = \frac{4}{5}

6 0
3 years ago
833.30/<br> 1-(1+0.00833)^-360
Fudgin [204]

Answer:

833.25 or 877.59

Step-by-step explanation:

I solved this in two different ways because I wasn't sure on how the question was meant to be read.

Attempt 1:

(833.3/1)-(1+0.00833)^-360

(1+0.00833)^-360 = 0.0505

so:

833.3 - 0.0505 = 833.25

Attempt 2:

833.3/(1-(1+0.00833)^-360)

1- 0.0505 = 0.9495

833.3/0.9495 = 877.59

3 0
2 years ago
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