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Galina-37 [17]
3 years ago
11

The graph of a trigonometric function oscillates between y=1 and y=-7. It reaches its

Mathematics
1 answer:
madam [21]3 years ago
4 0

Answer:

y = 4 sin(½ x) − 3

Step-by-step explanation:

The function is either sine or cosine:

y = A sin(2π/T x) + C

y = A cos(2π/T x) + C

where A is the amplitude, T is the period, and C is the midline.

The midline is the average of the min and max:

C = (1 + -7) / 2

C = -3

The amplitude is half the difference between the min and max:

A = (1 − -7) / 2

A = 4

The maximum is at x = π, and the minimum is at x = 3π.  The difference, 2π, is half the period.  So T = 4π.

Plugging in, the options are:

y = 4 sin(½ x) − 3

y = 4 cos(½ x) − 3

Since the maximum is at x = π, this must be a sine wave.

y = 4 sin(½ x) − 3

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The solution set of the inequality x ≥ - 4 using set builder notation and interval notation is {x | x ∈ Z, - 4 ≤ x ≤ ∞ } and [ - 4, ∞ ) respectively.

An inequality in mathematics is a relation that compares two numbers or other mathematical expressions in an unequal way.

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