Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
the bottom equation should be 18+30=3(6+10)
Step-by-step explanation:
6(3+10) = 18+60 which equals 78
78 does not equal 18
Answer:
Step-by-step explanation:
Saving the long, drawn out derivation of the formulas to find the x and y coordinates of the directed point, suffice it to say that it is:
x coordinate: 
and
y coordinate: 
where x1, x2, y1, and y2 are the coordinates from the given points and a and b are the numbers in the ratio, namely a = 3 and b = 4. Filling in accordingly:
the x coordinate of the directed point is
which simplifies down to -6, and
the y coordinate of the directed point is
which simplifies down to -1.
The coordinate of the point is (-6, -1). Write that down so you don't forget it.
Answer:
uh ok :
Step-by-step explanation:
A) false
3(5)-5
15-5
10
b)True
3(6)-5
18-5
13
c) false
3(7)-5
27-5
22
