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2 years ago

There are 8 squares and 2 circles. What is the simplest ratio of circles to total shapes?

Mathematics

1 answer:

nignag [31]2 years ago

8 0

Answer:

2:10 I think

Step-by-step explanation:

because there are 2 circles and 10 shapes in total (I'm not sure)

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Do any of you guys know the answer to this problem: 4 2/3 -3 1/3

vazorg [7]

The answer is 4/3 and I checked two times

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3 years ago

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This is a sketch of the curve with equation y = f(x).

Katen [24]

Answer:

We have to use the formule to calculate the vertex which is: V(-b/2a;4ac-b^2/4a)

A) y=x+7 where a=1 b=0 and c=7

By replacing we have: V(0;28/4) V(0;7)

B) y=-x where a=-1 b and c=0 so V(0,0)

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2 years ago

Mattttttthhhhhhhhhhhhhh , i need help

ale4655 [162]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have (0, 3) and (-10, 4)

Substitute:

$m=\dfrac{4-3}{-10-0}=\dfrac{1}{-10}\\\\y-3=-\dfrac{1}{10}(x-0)\qquad|\text{add 3 to both sides}\\\\y=-\dfrac{1}{10}x+3\to\boxed{A.}$

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2 years ago

Perform the indicated row operations, then write the new matrix.

Studentka2010 [4]

The matrix is not properly formatted.

However, I'm able to rearrange the question as:

$\left[\begin{array}{ccc}1&1&1|-1\\-2&3&5|3\\3&2&4|1\end{array}\right]$

Operations:

$2R_1 + R_2 ->R_2$

$-3R_1 +R_3 ->R_3$

Please note that the above may not reflect the original question. However, you should be able to implement my steps in your question.

Answer:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

Step-by-step explanation:

The first operation:

$2R_1 + R_2 ->R_2$

This means that the new second row (R2) is derived by:

Multiplying the first row (R1) by 2; add this to the second row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by 2

$2 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}2&2&2|-2\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}2&2&2|-2\end{array}\right] + \left[\begin{array}{ccc}-2&3&5|3\end{array}\right]$

$\left[\begin{array}{ccc}0&5&7|1\end{array}\right]$

The second operation:

$-3R_1 +R_3 ->R_3$

This means that the new third row (R3) is derived by:

Multiplying the first row (R1) by -3; add this to the third row

The row 1 elements are:

$\left[\begin{array}{ccc}1&1&1|-1\end{array}\right]$

Multiply by -3

$-3 * \left[\begin{array}{ccc}1&1&1|-1\end{array}\right] = \left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right]$

Add to row 2 elements are: $\left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}-3&-3&-3|3\end{array}\right] + \left[\begin{array}{ccc}3&2&4|1\end{array}\right]$

$\left[\begin{array}{ccc}0&-1&1|4\end{array}\right]$

Hence, the new matrix is:

$\left[\begin{array}{ccc}1&1&1|-1\\0&5&7|1\\0&-1&1|4\end{array}\right]$

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2 years ago

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Dennis has 80 nickels and dimes that equal up to $6.60 how many of each coin did he have

Tasya [4]

Answer:

im really confused soryy that i cant help

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2 years ago