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kirza4 [7]
3 years ago
6

PLS HELP WILL MARK BRAINLIEST On a piece of paper, draw a box plot to represent the data. Then determine

Mathematics
1 answer:
sineoko [7]3 years ago
8 0
D is correct. The median is 28, Q1 is 22, Q3 is 38
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Roberto wants to make $2.00 using half of dollar, and quarters.how many different ways can he make $2.00
Alik [6]
A half a dollar is 50 cents. If you want to use quarters, you would need 6 more quarters to make 2 dollars.
6 0
3 years ago
A new phone system was installed last year to help reduce the expense of personal calls that were being made by employees. Befor
Leya [2.2K]

Using the normal distribution, it is found that there was a 0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 700, \sigma = 50.

The probability of a month having a PCE between $575 and $790 is the <u>p-value of Z when X = 790 subtracted by the p-value of Z when X = 575</u>, hence:

X = 790:

Z = \frac{X - \mu}{\sigma}

Z = \frac{790 - 700}{50}

Z = 1.8

Z = 1.8 has a p-value of 0.9641.

X = 575:

Z = \frac{X - \mu}{\sigma}

Z = \frac{575 - 700}{50}

Z = -2.5

Z = -2.5 has a p-value of 0.0062.

0.9641 - 0.0062 = 0.9579.

0.9579 = 95.79% probability of a month having a PCE between $575 and $790.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
1 year ago
The sum of two numbers is 58. If their difference is 28, find both numbers
Alina [70]

Answer:

the numbers are 43 and 15

Step-by-step explanation:

Let the numbers are x and y

x+y=58

x-y=28

from that two equations,

2x=86

x=43

substitute x value in any equation we will get ,

y=15

7 0
3 years ago
Read 2 more answers
It is known that 5% of the population over the age of 30 in a city is a university graduate. Among the 100 people chosen randoml
Novosadov [1.4K]

Answer:

A) 1/3200000

B) 19/20

Step-by-step explanation:

Percentage population of graduates = 5

Proportion of graduates from 100 random samples = percentage × number of samples

Proportion of graduates = 0.05 × 100 = 5

Probability of having 5 graduates among the 100 random samples:

P(1 graduate) = possible outcome / total required outcome

P(1 graduate) = (5 / 100) = 1/20

P(5 graduates) = (1/20)^5

P(5 graduates) = 1/3200000

Probability of never being a graduate = (1 - probability of being a graduate)

Probability of never being a graduate = ( 1 - (1/20)) = 19/20

5 0
3 years ago
What is the common ratio for the geometric sequence? 18,12,8,163,… Enter your answer in the box.
uysha [10]

Answer:

\frac{2}{3}.

Step-by-step explanation:  

We have been given a geometric sequence 18,12,8,16/3,.. We are asked to find the common ratio of given geometric sequence.

We can find common ratio of geometric sequence by dividing any number by its previous number in the sequence.

\text{Common ratio of geometric sequence}=\frac{a_2}{a_1}

Let us use two consecutive numbers of our sequence in above formula.

a_2 will be 12 and a_1 will be 18 for our given sequence.

\text{Common ratio of geometric sequence}=\frac{12}{18}

Dividing our numerator and denominator by 6 we will get,

\text{Common ratio of geometric sequence}=\frac{2}{3}

Let us use numbers 8 and 16/3 in above formula.

\text{Common ratio of geometric sequence}=\frac{\frac{16}{3}}{8}

\text{Common ratio of geometric sequence}=\frac{16}{3*8}

\text{Common ratio of geometric sequence}=\frac{2}{3}

Therefore, we get \frac{2}{3} as common ratio of our given geometric sequence.




6 0
3 years ago
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