Answer:


Step-by-step explanation:
Given that A perfume company claims that the mean weight of ther new perfume is at least 8.9 fluid oz
For testing this claim, in Statistics we perform a certain measures called hypothesis testing.
For this first step is to create null and alternate hypothesis.
Normally null hypothesis would have some statistic = something
Here we want to test the mean weight of perfume
Hence null hypothesis would be
H0: mu = 8.9 fl oz.
Alternate hypothesis would be opposite of this claim
i.e.
Ha: mu ≠8.9 fluid oz
Hence answer is


Answer:
<h2>
![7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
</h2>
Solution,
![7( \sqrt[3]{2x} ) - 3( \sqrt[3]{16x} ) - 3( \sqrt[3]{8x} ) \\ = 7 \sqrt[3]{2x} - 3 \times ( \sqrt[3]{2 \times 2 \times 2 \times 2x} - 3 \times \sqrt[3]{2 \times 2 \times 2x} \\ = 7 \sqrt[3]{2x} - 3 \times (2 \sqrt[3]{2} x) - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 3 \times 2 \times \sqrt[3]{2x} - 3 \times 2x \\ = 7 \sqrt[3]{2x} - 6 \sqrt[3]{2x} - 6x](https://tex.z-dn.net/?f=7%28%20%5Csqrt%5B3%5D%7B2x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B16x%7D%20%29%20-%203%28%20%5Csqrt%5B3%5D%7B8x%7D%20%29%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%28%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20-%203%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2%20%5Ctimes%202%20%5Ctimes%202x%7D%20%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%20%282%20%5Csqrt%5B3%5D%7B2%7D%20x%29%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%203%20%5Ctimes%202x%20%5C%5C%20%20%3D%207%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206%20%5Csqrt%5B3%5D%7B2x%7D%20%20-%206x)
Hope this helps...
Good luck on your assignment...
Answer:
110
Step-by-step explanation:
So if add 75 + 35 you will get the number 110
Really hoped this helped
The answer is 8/7. 6/7 divided by 3/4 = 6/7 x 4/3. 6/7 x 4/3 = 24/21 = 8/7