2 years ago

SHOW ALL WORK

Mathematics

1 answer:

Lilit [14]2 years ago

5 0

Answer:

WHERE ARE THE PROBLEMS/VISUALS

BYE BCH

Step-by-step explanation:

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Simplify 4a – 7b + 2ab – a + b. -ab 15ab 4a – 7b + 2ab 3a – 6b + 2ab

gizmo_the_mogwai [7]

The answer is 3a-6b+2ab

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3 years ago

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I got the answer it is A I just need you to check it pls thank you

andrey2020 [161]

We have a circle of radius 5 m inside a square of side 10 m. The shaded area is:

$A_{\text{Shaded}}=A_{\text{Square}}-A_{\text{Circle}}$

Now, we calculate the area of the square and the circle:

$\begin{gathered} A_{\text{Square}}=10^2=100m^2 \\ A_{\text{Circle}}=\pi\cdot5^2=25\pi m^2 \end{gathered}$

Finally, the shaded area is:

$A_{\text{Shaded}}=100-25\pi\approx21.5m^2$

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6 months ago

If the circumference of a circle is 37.7 what is the diameter

Arada [10]

The diameter is 12 :)

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2 years ago

Combine the like terms -5.4v plus 0.3v

VladimirAG [237]

-5.4v+0.3v= -5.1v

Because both numbers have a common variable of 'v,' they can be combined.

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2 years ago

Please answer correctly will mark brainliest and will follow

Schach [20]

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Answer:

q/2, p, q

Step-by-step explanation:

You know the area of a triangle is half the product of base and height. The two triangles of interest here have base length p and height q/2. You're being asked to fill in the missing base or height dimension.

$=\dfrac{1}{2}\times p \times\boxed{\dfrac{q}{2}}+\dfrac{1}{2}\times\boxed{p}\times\dfrac{q}{2}\\\\=\dfrac{1}{2}\times p\times\boxed{q}$

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3 years ago