Answer:
40th and 80th visit
the first visit where you receive both is the 40th
Step-by-step explanation:
personally, I believe that the simplest way to solve this is use an excel spreadsheet to see which visits would include both a free beverage and a free appetizer:
- both rewards would happen only twice, at the 40th and 80th visit.
you can also calculate it mathematically since multiples of 8 and 10 do not repeat themselves very much, only when 8 is multiplied by 5 and 10.
Answer:
a)Null hypothesis:
Alternative hypothesis:
b) A Type of error I is reject the hypothesis that 
is equal to 40 when is fact ![\mu is equal to 40c) We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"Step-by-step explanation:Assuming this problem: "Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, [tex]\mu](https://tex.z-dn.net/?f=%5Cmu%20is%20%3Cstrong%3Eequal%20to%2040%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3Ec%29%20We%20can%20commit%20a%20Type%20II%20Error%2C%20since%20by%20definition%20%22A%20type%20II%20error%20is%20the%20non-rejection%20of%20a%20false%20null%20hypothesis%20and%20is%20known%20as%20%22false%20negative%22%20conclusion%22%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAssuming%20this%20problem%3A%3C%2Fstrong%3E%20%22Some%20college%20graduates%20employed%20full-time%20work%20more%20than%2040%20hours%20per%20week%2C%20and%20some%20work%20fewer%20than%2040%20hours%20per%20week.%20We%20suspect%20that%20the%20mean%20number%20of%20hours%20worked%20per%20week%20by%20college%20graduates%2C%20%5Btex%5D%5Cmu)
, is different from 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 43 hours and that the standard deviation is 4 hours. Based on this information, answer the questions below"
Data given
represent the sample mean
population mean (variable of interest)
s=4 represent the sample standard deviation
n represent the sample size
Part a: System of hypothesis
We need to conduct a hypothesis in order to determine if actual mean is different from 40 , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
Part b
In th context of this tes, what is a Type I error?
A Type of error I is reject the hypothesis that is equal to 40 when is fact [tex]\mu is equal to 40
Part c
Suppose that we decide not to reject the null hypothesis. What sort of error might we be making.
We can commit a Type II Error, since by definition "A type II error is the non-rejection of a false null hypothesis and is known as "false negative" conclusion"
Answer:
Pedro pagó $448
Step-by-step explanation:
Sea P el precio inicial de un objeto.
Si aplicamos un descuento del X%, entonces el nuevo precio del objeto es:
NP = P*(1 - X%/100%)
y lo que estamos ahorrando es:
P - NP
En este caso, primero tenemos un descuento del 30%, entonces:
NP = P*(1 - 30%/100%) = P*(1 - 0.3)
Luego tenemos otro descuento, esta vez del 20%, entonces:
NP' = NP*(1 - 20%/100%) = P*(1 - 0.3)*(1 - 20%/100%) = P*(1 - 0.3)*(1 - 0.2)
Lo que Pedro ahorra es igual a $352
entonces:
P - NP' = $352
P - P*(1 - 0.3)*(1 - 0.2) = $352
P*(1 - (1 - 0.3)*(1 - 0.2)) = $352
P*(1 - 0.56) = $352
P = $352/(1 - 0.56) = $800
Esto significa que el precio original era $800.
Y lo que pedro pago esta dado por la ecuación:
NP' = P*(1 - 0.2)*(1 - 0.3) = $800*(1 - 0.2)*(1 - 0.3) = $448.
