This statement is false<span>. Because the </span>base angles<span> of an </span>isosceles triangle<span> are</span>congruent<span>, if one </span>base angle<span> is a right </span>angle<span> then both </span>base angles<span> must be right</span>angles<span>. It is impossible to have a </span>triangle<span> with two right (90^\circ)</span>angles<span>.</span>
A way to remember what you have learned is creating notes or doing practice problems
A counterexample could be 2 inches and 10 inches.
My guess would probably be A = 21
Answer:
x = a(y+17)^2 + 2 where a < 0
Step-by-step explanation:
Since the parabola is horizontal, the formula of the parabola is x = a(y-h)^2 + k where (h,k) is the vertex.
Since it opens to the left, a must be negative. The vertex is (-17, 2), so h = -17 and k = 2.
Substituting these in, we find that the equation is
x = a(y+17)^2 + 2 where a is a real number that is less than 0 (i.e. negative)
I hope this helps! :)