<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>.</em>
<h3>
<em>Good</em><em> </em><em> </em><em>luck</em><em> </em><em>on </em><em>your</em><em> </em><em>as</em><em>signment</em></h3>
<em>-pragya~</em><em>~</em>
Answer:
2m↑3
Step-by-step explanation:
Answer:
Her weight is increase by 18 lbs over past five years and the slope is 3.6 lbs per year.
Step-by-step explanation:
Given information: Estelle weight is
At age 16 = 110 lbs
At age 21 = 128 ibs
Increase in her weight over the past 5 years is the difference of weight at age 21 and at age 16.
Increase in her weight over the past 5 years = 128 - 110 = 18
Her weight is increase by 18 lbs over past five years.
Let x=age and y=weight, then the weight function passes through the points (16,110) and (21,128).
If a line passes through two points
and
, then the slope of the line is

Using the above formula we get



Therefore the slope is 3.6 lbs per year.
The answer is a. You find the area of each shape and add them
You're looking for the largest number <em>x</em> such that
<em>x</em> ≡ 1 (mod 451)
<em>x</em> ≡ 4 (mod 328)
<em>x</em> ≡ 1 (mod 673)
Recall that
<em>x</em> ≡ <em>a</em> (mod <em>m</em>)
<em>x</em> ≡ <em>b</em> (mod <em>n</em>)
is solvable only when <em>a</em> ≡ <em>b</em> (mod gcd(<em>m</em>, <em>n</em>)). But this is not the case here; with <em>m</em> = 451 and <em>n</em> = 328, we have gcd(<em>m</em>, <em>n</em>) = 41, and clearly
1 ≡ 4 (mod 41)
is not true.
So there is no such number.