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Yanka [14]
3 years ago
6

which of the following inequalities matches the graph? graph of an inequality with a solid line through the points 0, negative 2

and 2, 1 with shading above the line
Mathematics
1 answer:
gladu [14]3 years ago
3 0
1) Equation of the line
Slope, m = [-2 -1]/[0 - 2] = -3 / -2 = 3/2y-intercept, b = -2
y = 3x/2 - 2

2) InequalityThe points over the line have y-coordinate greaetr than the value of the line, then
y ≥ 3x/2 - 2
2y ≥ 3x - 4
3x - 2y ≤ 4
3) Answer: 3x - 2y less than or equal to 4.
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Find the distance between each pair of points (6,-2) (8,-3)
alina1380 [7]

Answer:-1/2

Step-by-step explanation: You just find the slope which is m=y2-y1

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x2-x1

5 0
3 years ago
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Translate this inequality as SENTENCE :- x + 5 ≥ 10 <br>​
Scorpion4ik [409]

Answer:

A number plus 5 is greater then or equal to 10.

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2 years ago
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Graph a line with a slope of 3/4 that contains the point (2,-3).
arsen [322]

Answer:

Step-by-step explanation:

First, plot the point (2, -3) on the graph.  Then, use the slope to pick another point.  The slope is rise over run.  For your slope, the line will go 3 places up and then 4 places to the right.  Using a straight-edge, follow the points and you will get the graph of the line.

6 0
3 years ago
Please help me
Kruka [31]

y = x^2 -4x

x = -1

y = (-1)^2 - 4×-1=1+4 = 5

x= 0

y = (0)^2 - 4×0 = 0

x = 1

y = 1^2 -4×1 = 1-4 = -3

x = 2

y = 2^2 -4×2 = 4-8 = -4

x=3

y = 3^2 - 4×3 = 9-12 = -3

x = 4

y = 4^2 - 4×4 = 16 - 16 = 0

now 2nd equation

y = 2x^2 + x

x = -2

y = 2 (-2)^2 + (-2)= 8-2 = 6

x = -1

y = 2 (-1)^2+(-1)= 2-1 = 1

x = 0

y = 2(0)^2 +0 = 0

x = 1

y = 2 (1)^2 + 1 = 3

x = 2

y = 2(2)^2+2= 8 + 2 = 10

6 0
3 years ago
Factor the polynomial by grouping : x^3+5x^2-6x-30
andrew-mc [135]

The idea is to pair up the terms, factor each sub-group, and then pull out the overall GCF to fully factor.

x^3+5x^2-6x-30

(x^3+5x^2)+(-6x-30)

x^2(x+5)+(-6x-30)

x^2(x+5)-6(x+5)

(x^2-6)(x+5)

-------------

Answer: (x^2-6)(x+5)

4 0
3 years ago
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