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hjlf
2 years ago
12

HELPPPPPPPPPPPPPPPP WILL GIVE BRAINLIST

Mathematics
2 answers:
Dahasolnce [82]2 years ago
7 0

Answer: 6

Step-by-step explanation:

Increasing order and divide them into two equal group: 1, 2, 3, 3, 4, 4, 5, 5, 5, 6, 6 | 6, 6, 7, 7, 7, 8, 8, 8, 9, 9, 11

Kitty [74]2 years ago
6 0

it should be 8

to find median you line up the numbers in order and divide by 2

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What equation results from completing the square and then factoring? x^2+24x=33
Nezavi [6.7K]

Answer:

Its C but the way I got is too small so I cant really give explanation

7 0
3 years ago
What is the slope of the line? i-Ready Lesson Linear Equations and Slope Level H
nydimaria [60]

Answer:

Slope of the line = 2

Step-by-step explanation:

Slope of a line through two points lying on the line (x_1,y_1) and (x_2,y_2) is given by,

Slope = \frac{y_2-y_1}{x_2-x_1}

From the figure attached,

Given line is passing through two points (0, 1) and (1, 3).

Therefore, slope of the line will be,

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4 0
3 years ago
Lol what do I put so stuck
Sindrei [870]

Answer:

[See Below]

Step-by-step explanation:

Look at the "Fraction" column, all the fractions in this column must add up to 1 (because the whole bag contains only Red, Green, Blue or Other coloured beads).

So we work out the sum of missing fractions: \frac{1}{12} + \frac{1}{4} = \frac{1}{12} + \frac{3}{12} = \frac{4}{12} = \frac{1}{3}

And so we know the fractions in the missing boxes must add up to 1 - \frac{1}{3} = \frac{2}{3}.

This means that the number of blue and green beads is 2/3rds of the total number of beads in the bag. There are 12+4=16 blue+green beads so

\frac{2}{3} \times \text{Number of beads} = 16 \Rightarrow \text{Number of beads} = 24.

So if there are 24 beads in the bag, then the red beads are 1/12th of 24 which is 2 and the other beads are 1/4 of 24 which is 6.

Finally to complete the missing fractions: there are 12 blue beads and 24 in total so the fraction of blue beads is 12/24 = 1/2. Similarly, there are 4 green beads so the fraction of green beads is 4/24 = 1/6.

(I thought this was a very tricky question. Let me know in the comments if something doesn't make sense, or if you need more explanation on any part, or even if you spot an easier way to do it that I can't.)

5 0
3 years ago
How do you find vertical asymptotes?
Keith_Richards [23]
You just have to set the denominator to zero and solve for x
7 0
3 years ago
Cube root of b to the 12 power​
kvv77 [185]

\sqrt[3]{b^{12}}=\sqrt[3]{(b^4)^3}=b^4

6 0
2 years ago
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