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3 years ago

13

A child walks due east on the deck of a ship at 4 miles per hour. The ship is moving north at a speed of 18 miles per hour. Find

the speed and direction of the child relative to the surface of the water.

1 answer:

gladu [14]3 years ago

8 0

It's would be 24 that's the answer

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What is the sum of the measures of the interior angles of an octagon?

bazaltina [42]

Answer:

1080

Step-by-step explanation:

(n-2) × 180

(8-2) × 180= 1080

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3 years ago

Evaluate the expression.

son4ous [18]

Answer:

C

Step-by-step explanation:

at least two have to be in the same place (i think), and that’s the only one that does that

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4 years ago

Read 2 more answers

(1 point) A Bernoulli differential equation is one of the form dydx+P(x)y=Q(x)yn. Observe that, if n=0 or 1, the Bernoulli equat

andreyandreev [35.5K]

$y'-3xy=y^5x^3$

Divide both sides by $y^5$ :

$y^{-5}y'-3xy^{-4}=x^3$

Substitute $u(x)=y(x)^{-4}$ , so that $u'=-4y^{-5}y'$ . Then we get a new ODE that is linear in $u$ ,

$-\dfrac{u'}4-3xu=x^3\implies u'+12xu=4x^3$

Multiply both sides by $e^{6x^2}$ :

$e^{6x^2}u'+12xe^{6x^2}u=4x^3e^{6x^2}$

Notice that $\left(e^{6x^2}u(x)\right)'=e^{6x^2}u'(x)+12xe^{6x^2}u(x)$ . Integrating both sides with respect to $x$ gives

$\displaystyle\int\left(e^{6x^2}u\right)'\,\mathrm dx=e^{6x^2}u=\int 4x^3e^{6x^2}\,\mathrm dx$

$\implies u=\dfrac{e^{6x^2}(6x^2-1)}{18}+C$

$\implies y^4=\dfrac1{\frac{e^{6x^2}(6x^2-1)}{18}+C}$

Given that $y(1)=1$ , we find

$1=\dfrac1{\frac{5e^6}{18}+C}\implies C=\dfrac{18-5e^6}{18}$

so the particular solution is

$y^4=\dfrac1{\frac{e^{6x^2}(6x^2-1)}{18}+\frac{18-5e^6}{18}}$

$\implies\boxed{y=\sqrt[4]{\dfrac1{\frac{e^{6x^2}(6x^2-1)}{18}+\frac{18-5e^6}{18}}}}$

where we take the positive root because the initial condition tells us to expect $y>0$ when $x=1$ .

4 0

4 years ago

-4x2 + 2x - 5(1 + 3)<br> What expression is equivalent to the given expression?<br> or +<br> x2 +

DanielleElmas [232]

Answer:

-4x^2 -3x -5

Step-by-step explanation:

If you eliminate parentheses and collect terms, you get ...

-4x^2 +2x -5(1 +x)

= -4x^2 +2x -5 -5x

= -4x^2 +x(2 -5) -5

= -4x^2 -3x -5

6 0

3 years ago

Write the name of the period that has the digits 208

Naya [18.7K]

They teach the kids to group these. So the one spot, ten spot and hundred spot are called ONES PERIOD. The thousands, ten thousands and hundred thousands are grouped in THOUSANDS PERIOD. so in other words the number 208 would be a ONES PERIOD. Now let's say the number was 208,256 then 208 would be in the Thousands Period.

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3 years ago