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Wewaii [24]
3 years ago
6

The two bases of a trapezoid measure 14 inches and 10 inches respectively. The trapezoid's height is 8 inches. What is the area

of the trapezoid?
Mathematics
2 answers:
Karolina [17]3 years ago
8 0

Answer:

A.O.T=1/2×height(sum of bases)

Step-by-step explanation:

A.O.T=1/2×8(14+10)

=4(24)

= 96

julsineya [31]3 years ago
4 0

Answer:

96

Step-by-step explanation:

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Advandia is a drug used to treat diabetes, but it may cause an increase in heart attacks among a population already susceptible.
sergiy2304 [10]

Answer:

a) The proportions are not form matched-pairs data.

b) The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence of a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Step-by-step explanation:

a) Two data sets are "paired" when the following one-to-one relationship exists between values in the two data sets:

  • Each data set has the same number of data points.
  • Each data point in one data set is related to one, and only one, data point in the other data set.

None of this conditions apply in this case, so the proportions are not form matched-pairs data.

b) This is a hypothesis test for the difference between proportions.

The claim is that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

Then, the null and alternative hypothesis are:

H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2> 0

The significance level is 0.05.

The sample 1 (Avindia treatment), of size n1=1456 has a proportion of p1=0.0185.

p_1=X_1/n_1=27/1456=0.0185

The sample 2 (other treatment), of size n2=2895 has a proportion of p2=0.0142.

p_2=X_2/n_2=41/2895=0.0142

The difference between proportions is (p1-p2)=0.0044.

p_d=p_1-p_2=0.0185-0.0142=0.0044

The pooled proportion, needed to calculate the standard error, is:

p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{27+41}{1456+2895}=\dfrac{68}{4351}=0.0156

The estimated standard error of the difference between means is computed using the formula:

s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.0156*0.9844}{1456}+\dfrac{0.0156*0.9844}{2895}}\\\\\\s_{p1-p2}=\sqrt{0.00001+0.00001}=\sqrt{0.00002}=0.004

Then, we can calculate the z-statistic as:

z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.0044-0}{0.004}=\dfrac{0.0044}{0.004}=1.1

 

This test is a right-tailed test, so the P-value for this test is calculated as (using a z-table):

P-value=P(z>1.1)=0.1358

As the P-value (0.1358) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is  not enough evidence to support the claim that there is evidence to suggest that there is a significant increase in the proportion of people who suffer heart attacks when using Avandia compared to other treatments.

8 0
4 years ago
Read 2 more answers
2. The average height of every fifth member of the varsity football team was
MAVERICK [17]

Answer:

pppkmfk

Step-by-step explanation:

225nvinf jfvvi

dv

t

4w

5

4

346

4 0
3 years ago
The difference of eight and twice a number
Over [174]

Answer:

8 - 2x

Step-by-step explanation:

Let x be the unknown number

difference is subtraction

8 - 2x

4 0
3 years ago
GRAVITATION The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial vel
zhuklara [117]
<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>

h(t) = -16t^2 + 60t

<em><u>At what times will the object be at a height of 56 feet</u></em>

<em><u>Substitute h = 56</u></em>

56 = -16t^2 + 60t\\\\16t^2 - 60t + 56 = 0\\\\Divide\ the\ equation\ by\ 4\\\\4t^2 - 15t + 14=0

Solve the above equation by quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=4,\:b=-15,\:c=14\\\\x =\frac{-\left(-15\right)\pm \sqrt{\left(-15\right)^2-4\cdot \:4\cdot \:14}}{2\cdot \:4}\\\\Simplify\\\\x = \frac{15 \pm \sqrt{1}}{8}\\\\x = \frac{15 \pm 1}{8}\\\\We\ have\ two\ solutions\\\\x = \frac{15+1}{8} \text{ and } x = \frac{15-1}{8}\\\\x = 2 \text{ and } 1.75

Thus, at 2 second and 1.75 second, the object be at a height of 56 feet

5 0
4 years ago
Find a solution to the following system of equations.<br><br> −2x + y = −3<br> −x + 2y = 3
exis [7]
Multiply the first equation by -2 to give 

4x - 2y = 6
-x + 2y = 3     Adding:-
3x = 9
x = 3
Plug x = 3 into second equation:-
-3 + 2y = 3
2y = 6
y = 3


Answer is x=3, y = 3
5 0
3 years ago
Read 2 more answers
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