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3 years ago

PLEASE HELPPPPPPPPPPPPPPPPP

Mathematics

1 answer:

Stels [109]3 years ago

8 0

Answer:

Diameter = 43.96 $m^{2}$

Circumference = 153.86 $m^{2}$

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What’s the evaluation to 5x(2) + x for x =3

Mashcka [7]

Answer:

Step-by-step explanation:

5 x^2 +x

Let x = 3

5 * 3^2 +3

Exponents first

5 * 9+3

Multiply next

45+3

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3 years ago

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The vertex of this parabola is at 2, -1 When the y-value is 0 the x value is 5 what is the coefficient of the squared term in th

Olegator [25]

Answer:

$\large \boxed{\sf \frac{1}{9}}$

Step-by-step explanation:

$\sf y=a(x-h)^2+k$

$\sf Vertex = (h,k)$

y-value is 0 and the x value is 5

h = 2

k = -1

$\sf 0=a(5-2)^2+-1$

Solve for $\sf a$ (the coefficient of the squared term).

$\sf 0=a(3)^2+-1$

$\sf 0=9a-1$

$\sf 9a=1$

$\displaystyle \sf a=\frac{1}{9}$

The coefficient of the squared term in the parabola equation is 1/9.

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3 years ago

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An HMO charges $35 per doctor visit (d) and $15 per prescription (p). Which expression shows the total cost for prescriptions an

Alecsey [184]

Answer:

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Step-by-step explanation:

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3 years ago

Can u please help me with 27

Pachacha [2.7K]

The answer would be 237.375. To get this answer, you will first use the formula given for each unit. First, you will do the first unit by putting 8 to the third power, or basically 8x8x8. After you get the product 512, you will then do the next unit. Do that one by doing 6.5 to the third power, or as followed, 6.5x6.5x6.5. Once you get the product 274.625, you will then subtract that from 512. You will then receive the answer 237.375.

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3 years ago

Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou

faltersainse [42]

Answer:

$C.\ 104\ in^2$

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

$A_1=(6.5)(3)=19.5\ in^2$