Answer:
150°
Step-by-step explanation:
It is given that CosФ < 0 i.e CosФ is negative.
Therefore, the minimum the value of Ф for which CosФ <0 will be in the second quadrant i.e 90° < Ф < 180°.
Now it is also given that, Sin Ф =0.5 {the value of SinФ is positive because Sin value is positive in second quadrant.}
⇒ Ф =180° - Sin⁻¹ (0.5) = 180°-30° =150° (Answer)
100/9 good luck this should be right
Answer:
Total number of tables of first type = 23.
Total number of tables of second type = 7
Step-by-step explanation:
It is given that there are 30 tables in total and there are two types of tables.
Let's call the two seat tables, the first type as x and the second type as y.
∴ x + y = 30 ......(1)
Also a total number of 81 people are seated. Therefore, 2x number of people would be seated on the the first type and 5y on the second type. Hence the equation becomes:
2x + 5y = 81 .....(2)
To solve (1) & (2) Multiply (1) by 2 and subtract, we get:
y = 7
Substituting y = 7 in (1), we get x = 23.
∴ The number of tables of first kind = 23
The number of tables of second kind = 7
Answer:
The data table is attached below.
Step-by-step explanation:
The average of a set of data is the value that is a representative of the entire data set.
The formula to compute averages is:
Compute the average for drop 1 as follows:
![\bar x_{1}=\frac{1}{3}\times[10+11+9]=10](https://tex.z-dn.net/?f=%5Cbar%20x_%7B1%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B10%2B11%2B9%5D%3D10)
Compute the average for drop 2 as follows:
![\bar x_{2}=\frac{1}{3}\times[29+31+30]=30](https://tex.z-dn.net/?f=%5Cbar%20x_%7B2%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B29%2B31%2B30%5D%3D30)
Compute the average for drop 3 as follows:
![\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33](https://tex.z-dn.net/?f=%5Cbar%20x_%7B3%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B59%2B58%2B61%5D%3D59.33)
Compute the average for drop 4 as follows:
![\bar x_{4}=\frac{1}{3}\times[102+100+98]=100](https://tex.z-dn.net/?f=%5Cbar%20x_%7B4%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B102%2B100%2B98%5D%3D100)
Compute the average for drop 5 as follows:
![\bar x_{5}=\frac{1}{3}\times[122+125+127]=124.67](https://tex.z-dn.net/?f=%5Cbar%20x_%7B5%7D%3D%5Cfrac%7B1%7D%7B3%7D%5Ctimes%5B122%2B125%2B127%5D%3D124.67)
The data table is attached below.
Your answer could be b or d but I think it is b using the equation y=mx +b
