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Kobotan [32]
3 years ago
15

Which two security regulations does the PCI enforce with regard to electronic banking?

Computers and Technology
2 answers:
Sever21 [200]3 years ago
5 0

The two security regulations the PCI enforce in regards to electronic banking are an external Qualified Security Assessor (QSA) or by a firm specific Internal Security Assessor that creates a Report on Compliance for organizations handling large volumes of transactions, or by Self-Assessment Questionnaire (SAQ) for companies handling smaller volumes.

Vlada [557]3 years ago
3 0

The two security regulations the PCI enforce in regards to

electronic banking are an external Qualified Security Assessor (QSA) or by a

firm specific Internal Security Assessor that creates a Report on Compliance

for organizations handling large volumes of transactions, or by Self-Assessment

Questionnaire (SAQ) for companies handling smaller volumes.

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Hi! This is python coding. Please don't take advantage, actually, answer!
Greeley [361]

Answer:

Try and do number = 7

If that does not work then I dont know what to tell you.

Explanation:

8 0
3 years ago
The two types of one-time-password tokens are ______ and ______.
Nutka1998 [239]

Answer:

event based and time based

Explanation:

OTP tokens come in two types: event-based (HOTP) and time-based (TOTP). Event-based OTP tokens generate new codes at the press of the button and the code is valid until it is used by the application. Time-based OTP tokens generate codes that are valid only for a certain amount of time (eg, 30 or 60 seconds), after which a new code must be generated

5 0
4 years ago
Read 2 more answers
Given an input array of strings (characters) s, pick out the second column of data and convert it into a column vector of data.
hodyreva [135]

Answer:

Consider the following code.

Explanation:

save the following code in read_and_interp.m

 

function X = read_and_interp(s)

[m, n] = size(s);

X = zeros(m, 1);

for i = 1:m

if(str2num(s(i, 2:5)) == 9999)

% compute value based on previous and next entries in s array

% s(i, 2:5) retrieves columns 2-5 in ith row

X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;

else

X(i,1) = str2num(s(i,2:5));

end

end

end

======================

Now you can use teh function as shown below

s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];

read_and_interp(s)

output

ans =

96.000

114.000

109.500

105.000

112.000

7 0
3 years ago
Examine the efficiency the various recovery algorithms used in deadlock handling
sineoko [7]

Solution:

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This is the required answer.

4 0
3 years ago
If someone wouldn’t mind answering the first question for me
kompoz [17]

1.

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