Answer:
56
Step-by-step explanation:
80% is .8. Of means to multiply. So do .8 x 70 which comes out to 56.
I hope this helps! If you have anymore questions feel free to ask! :D
Answer:
120 grams
if they are all the same size
15.2 Is the answer...Hope this helps
Answer:
Part a)
Part b) 
Part c) (s+t) lie on Quadrant IV
Step-by-step explanation:
[Part a) Find sin(s+t)
we know that

step 1
Find sin(s)

we have

substitute




---> is positive because s lie on II Quadrant
step 2
Find cos(t)

we have

substitute




is negative because t lie on II Quadrant
step 3
Find sin(s+t)

we have



substitute the values



Part b) Find tan(s+t)
we know that
tex]tan(s + t) = (tan(s) + tan(t))/(1 - tan(s)tan(t))[/tex]
we have



step 1
Find tan(s)

substitute

step 2
Find tan(t)

substitute

step 3
Find tan(s+t)

substitute the values




Part c) Quadrant of s+t
we know that
----> (s+t) could be in III or IV quadrant
----> (s+t) could be in III or IV quadrant
Find the value of cos(s+t)

we have



substitute



we have that
-----> (s+t) could be in I or IV quadrant
----> (s+t) could be in III or IV quadrant
----> (s+t) could be in III or IV quadrant
therefore
(s+t) lie on Quadrant IV
Answer:
Step-by-step explanation:
15+9k