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kogti [31]
3 years ago
12

PLEASE HELP ME THANKS IF u do

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

The third one

Step-by-step explanation:

It can't be the first one since the peak is 4 since it is the highest

It can't be the second one because the data is all different

It could be the third one since their are gaps

And It can't be the fourth one because the range is 7

So it must be the third one

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Evaluate a^7 - 4b for a =3 and b= -1
Papessa [141]

Answer:

2187+4

= 2191

Step-by-step explanation:

plz brainliest :)

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3 years ago
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What are the coordinates of the centroid of a triangle with vertices P(−4, −1) , Q(2, 2) , and R(2, −3) ?
Alenkasestr [34]

Answer:

(x,y)=(0,\frac{-2}{3})

Step-by-step explanation:

Given : Vertices of Triangle P(x_1,y_1)=(-4,-1) , Q(x_2,y_2)=(2, 2) and R(x_3,y_3)=(2,-3)

To find : Centroid of a triangle

The centroid of a triangle is the point of intersection of the three medians of the triangle.

The formula to calculate the centroid of a triangle is:

(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})

Where, x_1,x_2,x_3,y_1,y_2,y_3  are the coordinates of the centroid

Substituting the values in the formula gives us:

(x,y)=(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3})

(x,y)=(\frac{-4+2+2}{3},\frac{-1+2-3}{3})

(x,y)=(\frac{0}{3},\frac{-2}{3})

Therefore, (x,y)=(0,\frac{-2}{3})

4 0
3 years ago
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If 1 cm = 0.394 inches, how many inches are in 1 kilometer?
Marta_Voda [28]
Since 1 km is 100,000 cm there are 39,400 inches in a kilometer
8 0
3 years ago
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Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably norma
Nataliya [291]

Answer:

The degrees of freedom is 11.

The proportion in a t-distribution less than -1.4 is 0.095.

Step-by-step explanation:

The complete question is:

Use a t-distribution to answer this question. Assume the samples are random samples from distributions that are reasonably normally distributed, and that a t-statistic will be used for inference about the difference in sample means. State the degrees of freedom used. Find the proportion in a t-distribution less than -1.4  if the samples have sizes 1 = 12 and n 2 = 12 . Enter the exact answer for the degrees of freedom and round your answer for the area to three decimal places. degrees of freedom = Enter your answer; degrees of freedom proportion = Enter your answer; proportion

Solution:

The information provided is:

n_{1}=n_{2}=12\\t-stat=-1.4

Compute the degrees of freedom as follows:

\text{df}=\text{Min}.(n_{1}-1,\ n_{2}-1)

   =\text{Min}.(12-1,\ 12-1)\\\\=\text{Min}.(11,\ 11)\\\\=11

Thus, the degrees of freedom is 11.

Compute the proportion in a t-distribution less than -1.4 as follows:

P(t_{df}

                      =P(t_{11}>1.4)\\\\=0.095

*Use a <em>t</em>-table.

Thus, the proportion in a t-distribution less than -1.4 is 0.095.

8 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
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