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Keith_Richards [23]
3 years ago
6

Write an expression that represents the area in square feet of each room in the house shown. Then

Mathematics
1 answer:
earnstyle [38]3 years ago
7 0

Answer:

Bedroom = x^2 ft^2

Closet = 25 ft^2

Bathroom = 6x ft^2

Total Area = x^2 + 6x + 25 ft^2

You might be interested in
BIOLOGY
kozerog [31]

Answer:

Step-by-step explanation:

Types of Angle Pairs

Adjacent angles: two angles with a common vertex, sharing a common side and no overlap.

Adjacent Angles

Angles ∠1 and ∠2 are adjacent.

Complementary angles: two angles, the sum of whose measures is 90°.

Complementary Angles

Angles ∠1 and ∠2 are complementary.

Complementary are these angles too(their sum is 90°):

Complementary Angles

Supplementary angles: two angles, the sum of whose measures is 180°.

Supplementary Angles

Angles ∠1 and ∠2 are supplementary.

 

Angle pairs formed by parallel lines cut by a transversal

When two parallel lines are given in a figure, there are two main areas: the interior and the exterior.  

When two parallel lines are cut by a third line, the third line is called the transversal. In the example below, eight angles are formed when parallel lines m and n are cut by a transversal line, t.  

There are several special pairs of angles formed from this figure. Some pairs have already been reviewed:  

Vertical pairs:

∠1 and ∠4  

∠2 and ∠3  

∠5 and ∠8  

∠6 and ∠7  

Recall that all pairs of vertical angles are congruent.  

Supplementary pairs:

∠1 and ∠2  

∠2 and ∠4  

∠3 and ∠4  

∠1 and ∠3  

∠5 and ∠6  

∠6 and ∠8  

∠7 and ∠8  

∠5 and ∠7  

Recall that supplementary angles are angles whose angle measure adds up to 180°. All of these supplementary pairs are linear pairs. There are other supplementary pairs described in the shortcut later in this section. There are three other special pairs of angles. These pairs are congruent pairs.

Alternate interior angles two angles in the interior of the parallel lines, and on opposite (alternate) sides of the transversal. Alternate interior angles are non-adjacent and congruent.  

 

Alternate exterior angles two angles in the exterior of the parallel lines, and on opposite (alternate) sides of the transversal. Alternate exterior angles are non-adjacent and congruent.  

 

Corresponding angles two angles, one in the interior and one in the exterior, that are on the same side of the transversal. Corresponding angles are non-adjacent and congruent.  

 

Use the following diagram of parallel lines cut by a transversal to answer the example problems.  

 

Example:  

What is the measure of ∠8?  

The angle marked with measure 53° and ∠8 are alternate exterior angles. They are in the exterior, on opposite sides of the transversal. Because they are congruent, the measure of ∠8 = 53°.  

Example:  

What is the measure of ∠7?  

∠8 and ∠7 are a linear pair; they are supplementary. Their measures add up to 180°. Therefore, ∠7 = 180° – 53° = 127°.

1. When a transversal cuts parallel lines, all of the acute angles formed are congruent, and all of the obtuse angles formed are congruent.  

 

In the figure above ∠1, ∠4, ∠5, and ∠7 are all acute angles. They are all congruent to each other. ∠1 ≅ ∠4 are vertical angles. ∠4 ≅ ∠5 are alternate interior angles, and ∠5 ≅ ∠7 are vertical angles. The same reasoning applies to the obtuse angles in the figure: ∠2, ∠3, ∠6, and ∠8 are all congruent to each other.

2. When parallel lines are cut by a transversal line, any one acute angle formed and any one obtuse angle formed are supplementary.  

 

From the figure, you can see that ∠3 and ∠4 are supplementary because they are a linear pair.

Notice also that ∠3 ≅ ∠7, since they are corresponding angles. Therefore, you can substitute ∠7 for ∠3 and know that ∠7 and ∠4 are supplementary.

Example:  

In the following figure, there are two parallel lines cut by a transversal. Which marked angle is supplementary to ∠1?  

 

The angle supplementary to ∠1 is ∠6. ∠1 is an obtuse angle, and any one acute angle, paired with any obtuse angle are supplementary angles. This is the only angle marked that is acute.

4 0
3 years ago
Hezekiel runs 1000 m at a rateof 3 minutes per km. how long does he take to run 500 m​
lana66690 [7]

Step-by-step explanation:

1 km = 1000 m

(hence the term "kilo" which means 1000).

so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.

now, we can see the solution already with our eyes.

but let's do it formally :

the rate or ratio between time and distance must be the same for the same speed.

so,

3 min / 1000 m = x min / 500 m

500 m × 3 min / 1000 m = x min

1/2 × 3 min = x min

3/2 = 1.5 min = x min

so, it takes him 1.5 minutes (90 seconds) to run 500 m.

3 0
3 years ago
HELP TIMED BRAINLIST
lesya692 [45]

Answer:

it's D

Step-by-step explanation:

You use distribute property, then add all like terms

3 0
3 years ago
Read 2 more answers
What is the slope in the Y intercept of the line on the graph below
Archy [21]

Answer:

just by looking at the graph you can see that the y int is one, so that eliminates two answers already. Then the slope is rise over run. (best thing to remember in math. rise over run) so pick two points. (0, 1) and (4,0) were the first ones i saw. to get from those two points you go from (0,1) over 4 (thats your run) and from there down 1 (thats your rise) to get to (0,4). You would then do rise over run (and because your rise goes down its negative) to get -1/4 as your slope. The answer is slope= -1/4, Y intercept = 1

6 0
3 years ago
The denominator of a fraction is 4 more than the numerator if both are decreased by 3 the simplified result is 6/7 find original
Hitman42 [59]

<u>Answer:</u>

The denominator of a fraction is 4 more than the numerator. The original fraction is \frac{27}{31}

<u>Solution:</u>

Given that  

Denominator of fraction is 4 more than the numerator.

Let’s say numerator of fraction be represented by variable x.

So denominator of a faction as it is four more that numerator will be x + 4

Also given if both decreased by three than simplified result is \frac{6}{7}

=>\frac{(x-3)}{((x+4)-3)}=\frac{6}{7}

Solving above equation for x

=> 7(x – 3  ) = 6 ( x + 1 )

=> 7x – 21 = 6x + 6

=> 7x – 6x = 6 + 21

=> x = 27

Numerator of fraction = x = 27

Denominator of fraction = x + 4 = 27 + 4 = 31

\text {required fraction}=\frac{\text {numerator}}{\text {denominator}}

= \frac{27}{31}

Hence the original fraction is \frac{27}{31}

7 0
4 years ago
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