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Schach [20]
3 years ago
12

Your friend can clap his hands 28 times in 12 seconds. How many times can your friend clap his hands in 0.5 minute?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
60 seconds in a minute

12 goes into 60, 5 times,
So 5 * 28 = 140
140 claps per minute

0.5 minute is 30 seconds, half a minute so divide by 2,
140/2 = 70

70 times every 0.5 minutes
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Given \qquad m \angle aoc = 108^\circm∠aoc=108 ​∘ ​​ space, m, angle, a, o, c, equals, 108, degree \qquad m \angle aob = 3x + 4^
tamaranim1 [39]

Answer:

Step-by-step explanation:

Given the following angle

We want to find angle AOB

∠AOC = 108°

∠AOB = 3x+4

∠BOC =8x−28 ​

Check attachment for understanding

From the attachment, we notice that the sum of angle AOB and angle BOC equals to angle AOC.

∠AOB + ∠BOC = ∠AOC

3x + 4 + 8x —28 = 108

3x + 8x + 4—28 = 108

11x — 24 = 108

11x = 108 + 24

11x = 132

x = 132/11

x = 12°

∠AOB = 3x+4

∠AOB = 3(12) + 4

∠AOB = 36+4

∠AOB =  40°

Extra

∠BOC = 8x−28

∠BOC = 8(12)−28

∠BOC = 96−28

∠BOC = 68°

6 0
3 years ago
Read 2 more answers
In an arithmetic sequence, a_17 = -40 and a_28 = -73. Please explain how to use this information to write a recursive formula fo
Vinvika [58]

An arithmetic sequence

a_1,a_2,a_3,\ldots,a_n,\ldots

is one in which consecutive terms of the sequence differ by a fixed number, call it <em>d</em>. This means that, given the first term a_1, we can build the sequence by simply adding <em>d</em> :

a_2=a_1+d

a_3=a_2+d

a_4=a_3+d

and so on, the general pattern governed by the recursive rule,

a_n=a_{n-1}+d

We can exploit this rule in order to write any term of the sequence in terms of the first one. For example,

a_3=a_2+d=(a_1+d)+d=a_1+2d

a_4=a_3+d=(a_1+2d)+d=a_1+3d

and so on up to

a_n=a_1+(n-1)d

In this case, we're not given the first term right away, but the 17th. But this isn't a problem; we can use the same exploit to get

a_{18}=a_{17}+d

a_{19}=a_{17}+2d

a_{20}=a_{17}+3d

and so on, up to the next term we know,

a_{28}=a_{17}+11d=-40+11d

(Notice how the subscript of <em>a</em> on the right and the coefficient of <em>d</em> add up to the subscript of <em>a</em> on the left.)

The 28th term is -73, so we can solve for <em>d</em> :

-73=-40+11d\implies -33=11d\implies d=-3

To get the first term of the sequence, we use the rule found above and either of the known values of the sequence. For instance,

a_{17}=a_1+16d\implies-40=a_1-16\cdot3\implies a_1=8

Then the recursive rule for this particular sequence is

\begin{cases}a_1=8\\a_n=a_{n-1}-3&\text{for }n>1\end{cases}

7 0
3 years ago
Explain how you know that the equation 3x = 9 is equivalent to the equation x =3.
Marat540 [252]

Hey there!

If x = 3 then substitute it into the equation

3(3) = 9

3(3) = 9

9 = 9

Answer: 9 = 9, so this makes this statement is true

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0
3 years ago
Solve the system of equations using any method.
stiv31 [10]

Answer:

My answer what I came up with is B And B

4 0
3 years ago
I need help ASAP if you can help you are amazing.
olchik [2.2K]

Answer (Note: the bold are answers):

First question answer:

Point = (3,1)

Slope = 3

y = 3x + b

(1) = 3(3) + b

1 = 9 + b

1 - 9 = b

-8 = b

y = 3x - 8

The second question answer:

y = mx + b

Get two points:

(3,-7) and (4,-11)

m = -11 - (-7) / 4 - 3

m = -11 + 7 / 1

m = -4 / 1

m = -4

b = + 3

y = -4x + 3

3 0
3 years ago
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