Answer:
The probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
Step-by-step explanation:
Consider the provided information.
It is given that mean is 440 seconds and standard deviation is 60 seconds.
z factor for less than 302 seconds would be: 
z = (302 - 440) / 60 = -2.3
The probability of getting a z factor of less than -2.3 = 0.0107 approximately.
looking up in the z-table for a z factor of -2.3.
The probability of a student running the mile in less then 302 seconds would be 0.0107.
Hence, the probability that a randomly selected boy in secondary school can run the mile in less than 302 seconds is 0.0107
Answer:
as a fraction = 75/92
as a percentage = 81.52%
Step-by-step explanation:
total no of students = 92
probability that a student has hazel or brown eyes = Pr(hazel or brown)
but probability of a or b happening ie Pr(a or b) simply is Pr (a) +Pr (b)
therefore Pr(hazel or brown) = Pr(hazel)+ Pr(brown)
Pr(brown) = (no of brown eyes )/(total set of eyes)
= 
= 10/23
Pr( hazel) = (no of hazel eyes )/(total set of eyes)
= 
=35/92
hence Pr(hazel or brown) = (10/23) + (35/92) =75/92
so there's 75/92 probability (or 0.8 out of 1 chance )to choose either hazel or brown randomly
To multiply two fractions together, multiply the numerators of both fractions together and same goes for the denominators.
Simplify.
So, 1/3 is the answer.
I think it would be 50% let’s hope
I could be very wrong, but I believe the answer is C
