<img src="https://tex.z-dn.net/?f=%5Csqrt%7B18%7D%2B%5Csqrt%7B50%7D" id="TexFormula1" title="\sqrt{18}+\sqrt{50}" alt="\sqrt{18}

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AURORKA [14]

2 years ago

+\sqrt{50}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

Svetllana [295]2 years ago

8 0

Answer:

8√2

Step-by-step explanation:

Both 18 and 50 are easily factorable, the first as 2*9 and the second as 2*25. Taking the square root of 18 results in 3√2 and that of 50 in 5√2/

Thus, the original problem √18 + √50 simplifies to (3 + 5)√2, or 8√2

KengaRu [80]2 years ago

3 0

$3\sqrt{2} +5\sqrt2}\\=8\sqrt{2}$

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Answer:

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Step-by-step explanation:

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3th

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Answer:

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The question might have some mistake since there are 2 multiplier of t. I found a similar question as follows:

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