Answer:
(1,1)? Sorry im not completely sure
Answer:
wow this your first Q
Step-by-step explanation:
Answer:
(2,10) or x=2 y=10
Step-by-step explanation:
<em>1. Pick one of your equations and solve for a variable. I chose the first equation and solved for x.</em>
5x-2y=-10 (Move the -2y to the other side, you need to do the opposite so you add +2y to -10)
5x=2y-10 (Divide the 5 from the x)
x=2/5y-2
<em>2. Now take what you got for x and plug it into the x variable on the other equation.</em>
3(2/5y-2)+6y=66 (Multiply 3 by 2/5y and -2)
6/5y-6=6y=66 (Move the -6 to the other side and add 6/5y to 6y)
36/5y=72 (Since the number on the y is a fraction, you must do the opposite to the other side)
y=72/1 x 5/36 (Flip your fraction and multiply it by the 72)
y=10
<em>3. Now that you have one of the variables solved for, in order to get the other we must plug in what we have to the first equation.</em>
5x-2(10)=-10 (Multiple 2 by 10)
5x-20=-10 (Move -20 to the other side, since you do the opposite add +20 to the -10)
5x=10 ( Divide 10 by 5)
x= 2
<em>4. If needed, plug in the values of x and y to check your solution.</em>
Hope this could help! :)
the answer is the last one
1+tan^2(A) = sec^2(A) [Pythagorean Identities]
tan^2(A)cot(A) = tan(A)[tan(A)cot(A)] = tan(A)[1] = tan(A)
*see photo for complete solution*
