No, bc 3/5 is 3/5. 6/8 reduced is 3/4. So no
Correct answer is: (0,7843) and (10,8793)
Solution:-
Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.
We have to write this data as (x,y) .
Where x= years after 1990 and y=number of students enrolled.
Since in 1990, 7843 students enrolled, x = 1990-1990=0
And y=7843.
Hence one ordered pair is (0,7843).
Let us find the years after 1990 for 2000 = 2000-1990 =10
Hence another ordered pair is (10,8793).
Idk but it's 0.416667
cuz 25/60 equals so
<span>I note that this problem starts out with "Which is a factor of ... " This implies that you were given several answer choices. If that's the case, it's unfortunate that you haven't shared them.
I thought I'd try finding roots of this function using synthetic division. See below:
f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35
Please use " ^ " to denote exponentiation. Thanks.
Possible zeros of this poly are factors of 35: plus or minus 1, plus or minus 5, plus or minus 7. Use synthetic division; determine whether or not there is a non-zero remainder in each case. If none of these work, form rational divisors from 35 and 6 and try them: 5/6, 7/6, 1/6, etc.
Provided that you have copied down the function
</span>f(x) = 6x^4 – 21x^3 – 4x^2 + 24x – 35 properly, this approach will eventually turn up 1 or 2 zeros of this poly. Obviously it'd be much easier if you'd check out the possible answers given you with this problem.
By graphing this function, I found that the graph crosses the x-axis at 7/2. There is another root.
Using synth. div. to check whether or not 7/2 is a root:
___________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
----------- ------------------------------
6 0 -4 10 0
Because the remainder is zero, 7/2 (or 3.5) is a root of the polynomial. Thus, (x-3.5), or (x-7/2), is a factor.
