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ivann1987 [24]
2 years ago
11

Prove that 1÷loga ab + 1÷logb ab=1​

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
6 0

Answer:

See below.

Step-by-step explanation:

1 ÷ loga ab + 1 ÷ logb ab

=  1 / (loga ab)  +   1 /  (loga ab / loga b)    { change of log base)

= 1 / (loga ab) +  loga b / (loga ab)

=  (1 + loga b) / loga ab

=  (1 + loga b) / (loga a + loga b)    Now loga a = 1 so we have:

((1 + loga b) / (1 + loga b)

= 1.

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