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SpyIntel [72]
3 years ago
7

Part C: What is the width 'w' of the painting? Round your answer to the nearest tenth.

Mathematics
2 answers:
Leto [7]3 years ago
8 0
The width of the painting is either -14.8 or 8.8
muminat3 years ago
5 0
8.8.









Explain: Whegshshhs
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Step-by-step explanation:

given f(x) = sin(x) + cos(x)

f(x) can be rewritten as \sqrt{2} [\frac{sin(x)}{\sqrt{2} }+\frac{cos(x)}{\sqrt{2} }  ]..................(a)\\\\\ \frac{1}{\sqrt{2} } = cos(45) = sin(45)\\\\

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f '(x) = f '(x)=\sqrt{2}  \frac{dsin(45+x)}{dx}\\ \\f'(x)=\sqrt{2} cos(45+x)\\\\f'(x)>0=>\sqrt{2} cos(45+x)>0

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we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]

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2) π/4 + x > 3π/2  => x > 5π/4  => x∈[5π/4,2π]

from conditions 1 and 2 we have  x∈(0,π/4)∪(5π/4,2π)

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Step-by-step explanation:

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