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3 years ago

What is the solution (a, b) to this system of linear equations?

Mathematics

2 answers:

jeka57 [31]3 years ago

6 0

Answer:

a=1, b=7. (1, 7).

Step-by-step explanation:

3a+6b=45

2a-2b=-12

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simplify 3a+6b=45 into a+2b=15

and 2a-2b=-12 into a-b=-6

--------------------

a+2b=15

a-b=-6

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a+2b=15

-(a-b)=-(-6)

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a+2b=15

-a+b=6

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3b=21

b=21/3

b=7

a+2(7)=15

a+14=15

a=15-14

a=1

lys-0071 [83]3 years ago

4 0

Answer:

the ansewer is (C)(1,7)

Step-by-step explanation:

hope it helps

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A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

Fencing required = 1586 m

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use Cosine Rule to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = 1586 m

Fencing required = 1586 m

4 0

3 years ago

Solve a/a-1 - a+5/a =0

sweet [91]

The answer should be 5/a-a=0

4 0

3 years ago

Find the distance between (-1,-2) and (8,9)

Rom4ik [11]

Answer:

$\sqrt{202}$ units or 14.2 units (rounded to the nearest tenth)

Step-by-step explanation:

To find the distance between a pair of two points, use the distance formula $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ . Substitute the x and y values of (-1,-2) and (8,9) into the formula and simplify:

$d = \sqrt{(-1-8)^2+(-2-9)^2} \\d = \sqrt{(-9)^2+(-11)^2} \\d = \sqrt{81+121} \\d= \sqrt{202}$

So, as an exact answer, the distance is $\sqrt{202}$ units.

(To find the decimal approximate of that answer, enter it into a calculator. This would make the decimal approximate 14.2 units, when rounded to the nearest tenth.)

7 0

3 years ago

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konstantin123 [22]

Answer:

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Step-by-step explanation:.

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3 years ago

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