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Determinar la longitud de la hipotenusa del siguiente triángulo si se conocen las medidas que se indican de los demás triángulos

Zina [86]

it helps a lot in math us it won't let me do it

3 0

3 years ago

Will GIVE 200 Points!!! NEED HELP ASAP!!!! PLEASE HURRY AND HELP!!! For the given statement, write the converse, inverse, and co

UNO [17]

Answer:

See explanation

Step-by-step explanation:

Consider given statement "If a figure is a cube, then it has eight vertices" in math terms. Let

statement p be "A figure is cube.";
statement q be "A figure has 8 vertices."

Then the statement "If a figure is a cube, then it has eight vertices" can be written as

$p\Rightarrow q$

Converse ( $q\Rightarrow p$ ): If a figure has eight vertices, then it is a cube.

Inverse ( $\neg p\Rightarrow \neg q$ ): If a figure is not a cube, then it has not eight vertices.

Contrapositive ( $\neg q\Rightarrow \neg p$ ): If a figure has not eight vertices, then it is not a cube.

7 0

3 years ago

Please help this is timed

max2010maxim [7]

Answer:

The last one (f) hope u still have time

7 0

3 years ago

What is the equation of the quadratic graph with a focus of (3, 1) and a directrix of y = 5?

telo118 [61]

Answer:

$f(x)=-\frac{1}{8}(x-3)^2+3$

Step-by-step explanation:

We want to find the equation of the parabola with a focus of $(3,1)$ and directrix $y=5$ .

Considering the directrix, the quadratic graph must open downwards.

The equation of this parabola is given by the formula,

$(x-h)^2=4p(y-k)$ , where $(h,k)$ is the vertex of the parabola.

The axis of this parabola meets the directrix at $(3,5)$ .

Since the vertex is the midpoint of the focus and the point of intersection of the axis of the parabola and the directrix,

$h=\frac{3+3}{2}=3$ and $k=\frac{5+1}{2}=3$ .

The equation of the parabola now becomes,

$(x-3)^2=4p(y-3)$ .

Also $|p|$ is the distance between the vertex and the directrix.

$|p|=2$

This implies that $p=-2\:or\:2$ .

Since the parabola turns downwards,

$p=-2$ .

Our equation now becomes,

$(x-3)^2=4(-2)(y-3)$ .

$(x-3)^2=-8(y-3)$ .

We make y the subject to get,

$y=-\frac{1}{8}(x-3)^2+3)$ .

This is the same as

$f(x)=-\frac{1}{8}(x-3)^2+3)$ .

4 0

3 years ago

A bowling leagues mean score is 197 with a standard deviation of 12. The scores are normally distributed. What is the probabilit

Bond [772]

Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that $\mu = 197, \sigma = 12$

What is the probability a given player averaged less than 190?

This is the p-value of Z when X = 190.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{190 - 197}{12}$

$Z = -0.58$

$Z = -0.58$ has a p-value of 0.281.

0.281 = 28.1% probability a given player averaged less than 190.

8 0

3 years ago