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kvv77 [185]
3 years ago
14

Grass starts with 30,000 kcal of energy. A cheetah would acquire

Biology
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

300 kcal of energy.

Explanation:

Grass produces 30,000 kcal of energy through the process of photosynthesis. The zebra eat this grass and would acquire 3000  kcal of energy because only 10% of energy will transferred from one trophic level to another. In this way, when the cheetah feed on zebra, it acquire 300  kcal of energy and again 10% of energy is transferred from zebra to cheetah while the remaining release in the atmosphere in the form of heat energy.

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How are evolution and allele frequency connected?
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Help please! DNA Assignment
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DNA Replication:

Replicate the following strand of DNA:

Original DNA: A T G A A C CA T T C A G T A T G G

Complementary DNA:

Remember that the complimentary base pairs in DNA are Adenine-Thymine and Guanine-Cytosine, or A-T and G-C. This means that if the original sequence is:

A T G A A C C A T T C A G T A T G G

Then the compliment is (replace with the opposite base pairs):

T A C T T G G T A A G T C A T A C C

Transcription:

Transcribe the DNA to make an mRNA molecule

COMPLIMENTARY DNA:

mRNA Molecule:

So if our complimentary DNA (antisense stand) is T A C T T G G T A A G T C A T A C C then to transcribe, we basically create another complimentary strand, but for mRNA, we use Uracil instead of Thymine:

A U G A A C C A U U C A G U A U G G  

Translation:

Translate the mRNA into the corresponding amino acids.

mRNA MOLECULE:

AMINO ACID:

Using the DNA sequence provided, determine the amino acids.

Next, take each codon (3-base set) to the table and record the corresponding protein:

A U G = Methionine (start)

A A C = Asparagine

C A U = Histidine

U C A = Serine

G U A = Valine

U G G = Tryptophan

ORIGINAL DNA: A T G G G T C T A G C G A A A G A T

Complementary DNA:

mRNA DNA Molecule:

Amino Acid:

And we do it all again:

A T G G G T C T A G C G A A A G A T = original DNA

T A C C C A G A T C G C T T T C T A = complementry DNA

A U G G G U C U A G C G A A A G A U = mRNA

A U G = Methionine (start)

G G U = Glysine

C U A = Leucine

G C G = Alanine

A A A = Lysine

G A U = Aspartate

Explanation:

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