PLEASE HELP FASTT

Mathematics

1 answer:

denpristay [2]3 years ago

8 0

Answer:

y = -3x + 1

Step-by-step explanation:

Plug in your x (2) and y (-5) values into your slope-intercept formula (y=mx+b).

-5 = -3(2) +b

Solve for b:

-5 = -3(2) + b

-5 = -6 + b

1 = b

Plug in the value of b, and the slope (-3) for the formula:

y = -3x + 1

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Please Help!!!!!! So i know how to reflect over line y=-x but how would i do it over line y=-x+6. An example would be helpful an

Westkost [7]

To reflect in the line y = -x + 6, we translate everything down 6 first. This will make it seem like we are reflecting in the line y = -x
                                 (x,y) → (x, y-6)
Then, to reflect in the line y = -x, we switch the x- and y-coordinates and then make them negative
                                 (x,y) → (-(y-6), -x)
Then we move everything back up again
                                 (x,y) → (-(y-6), -x + 6)
I will present to you an example. Reflect the point (-4, 8) in the line y = -x + 6.
                                 (-4,8) → (-(8-6), -(-4) + 6) → (-2, 10)
You should graph this out to confirm with the reflection line.

4 0

4 years ago

Find the distance from point A(−1, 7) to the line y=3x. Round your answer to the nearest tenth.

bearhunter [10]

Answer:

The distance from the point to the line is approximately 3.2 units

Step-by-step explanation:

Distance From a Point to a Line

Is the shortest distance from a given point to any point on an infinite straight line. The shortest distance occurs when the segment from the point and the line are perpendiculars.

If the line is given by the equation ax + by + c = 0, where a, b and c are real constants, the distance from the line to a point (x0,y0) is

$\displaystyle d= \frac{|ax_0+by_0+c|}{\sqrt{a^2+b^2}}$