Question

3x^+5x+2=0 need work shown plz

Answer 1

Answer:

${3x}^{2} + 5x + 2 \\ = {3x}^{2} + 3x + 2x + 2 \\ = 3x(x + 1) + 2(x + 1) \\ = (3x +2)(x + 1)$

Answer 2

Answer:

x=-2/3 and x=-1

factored form

(3x+2)(x+1)

[Let me know if there is another method your instructor wanted you to use]

Step-by-step explanation:

Given:

$3x^2+5x+2=0$

Factor using the quadratic formula:

$x=\frac{-b+-\sqrt{b^2-4(a)(c)} }{2a}$

$x=\frac{-5+-\sqrt{(5)^2-4(3)(2)} }{2(3)}$

$x=\frac{-5+-\sqrt{25-24} }{6}$

$x=\frac{-5+-\sqrt{1} }{6}$

$x=\frac{-5+1}{6}$ and $x=\frac{-5-1}{6}$

Finally:

$x=-2/3$ and $x=-1$

Written in factored form would be:

$(3x+2)(x+1)$