Please help!! What is the solution to 2x^2+x+2=0?

Mathematics

1 answer:

Aliun [14]3 years ago

8 0

Answer:

your 3rd option

Step-by-step explanation:

$\frac{-1+/-\sqrt{1-4(2)(2} )}{2(2)}$

${\frac{-1+/-\sqrt{1-16} }{4}}$

${\frac{-1+/-\sqrt{-15} }{4}}$

${\frac{-1+/-i\sqrt{15} }{4}}$

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Consider the two triangles.

GuDViN [60]

Answer:

(A)Show that the ratios StartFraction U V Over X Y EndFraction , StartFraction W U Over Z X EndFraction , and StartFraction W V Over Z Y EndFraction are equivalent.

$\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}$

Step-by-step explanation:

In Triangles WUV and XZY:

$\angle VUW$ and \angle YXZ$ are congruent. \\\angle U W V$ and \angle X Z Y$ are congruent.\\ \angle U V W$ and \angle Z Y X$ are congruent.$

Therefore:

$\triangle UWV \cong \triangle XZY$

To show that the triangles are similar by the SSS similarity theorem, we have:

$\dfrac{UW}{XZ}=\dfrac{WV}{ZY}=\dfrac{UV}{XY}$

As a check:

$\dfrac{UW}{XZ}=\dfrac{40}{32}=1.25\\\\\dfrac{WV}{ZY}=\dfrac{60}{48}=1.25\\\\\dfrac{UV}{XY}=\dfrac{50}{40}=1.25$

The correct option is A.

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3 years ago

What is the simplified form of 4x plus 2 over x plus 5 minus the fraction 3x plus 1 over x plus 5?

viva [34]

We have that

[(4x+2)/(x+5)]-[(3x+1)/(x+5)]
<span>They have common denominators, so just add the numerators like normal fractions:</span>
=[(4x+2)-(3x+1)]/(x+5)
=[(4x+2-3x-1)]/(x+5)
=[(x+1)]/(x+5)

the answer is
(x+1)/(x+5)

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Step-by-step explanation:

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