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Pie
2 years ago
15

Please help!! What is the solution to 2x^2+x+2=0?

Mathematics
1 answer:
Aliun [14]2 years ago
8 0

Answer:

your 3rd option

Step-by-step explanation:

\frac{-1+/-\sqrt{1-4(2)(2} )}{2(2)}

{\frac{-1+/-\sqrt{1-16} }{4}}

{\frac{-1+/-\sqrt{-15} }{4}}

{\frac{-1+/-i\sqrt{15} }{4}}

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A. y = 3x.

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A cylindrical water tank is 1.2 meters high and has a diameter of 4.6 meters. Approximately how much cubic meters of water will
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So what you need to do is find the volume and divide it by 2.
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An equilateral triangle has a side length of 6. What is the height of the triangle?
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Since the height of an equilateral triangle in terms of its side s is s√3/2, the height of the triangle is 6√3/2 = 3√3 and so the area is (1/2)(6)(3√3) = 9√3. 

<span>If we draw a horizontal line a height of h from the base of the triangle, the region is split into two regions: the lower region consisting of a trapezoid of height h and the upper region consisting of a triangle of height 3√3 - h. </span>

<span>Since the upper triangle and the triangle itself are similar triangles, the base and height are proportional. If we let x denote the base of the length of the upper triangle, we have: </span>

<span>(S. of small triangle)/(S. of big triangle) = (Ht. of small triangle)/(Ht. of big triangle) </span>
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<span>A = (1/2)[(6√3 - 2h)/√3](3√3 - h) = [(6√3 - 2h)(3√3 - h)]/(2√3). </span>
<span>(Made a dumb mistake about the height here for some reason) </span>

<span>Since we require that the area of this triangle is to be half of the total area (9√3/2), we need to solve: </span>

<span>[(6√3 - 2h)(3√3 - h)]/(2√3) = 9√3/2 </span>
<span>==> (6√3 - 2h)(3√3 - h) = 27 </span>
<span>==> 54 - 6h√3 - 6h√3 + 2h^2 = 27 </span>
<span>==> 2h^2 - 12h√3 + 27 = 0. </span>

<span>Solving with the Quadratic Formula gives: </span>

<span>h = (6√3 + 3√6)/2 ≈ 8.87 units and h = (6√3 - 3√6)/2 ≈ 1.52 units. </span>

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<span>Therefore, the line should be ==> (6√3 - 3√6)/2 units from the base. </span>

<span>I hope this helps! ^^ Brainliest Please?</span><span>
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