Answer:
i dont under your question. Do you mean on triangles or complamentary or supplementary angles it depends
Answer:
∠ XZY ≈ 23.6°
Step-by-step explanation:
Using the sine ratio in the right triangle, that is
sinXZY =
=
=
, then
∠ XZY =
(
) ≈ 23.6° ( to 1 dec. place )
(12x +15)°=75° .…(शिर्षभिमुख कोण भएर)
or, 12x+15=75
or, 12x=75-15
or, 12x=60
or, x=60÷12
or, x=5
(6y-27)°=105° .…(शिर्षभिमुख कोण भएर)
or, 6y-27=105
or, 6y=105+27
or, 6y=132
or, y=132÷6
or, y=22
Answer:
f(x) = x⁴-6x³-13x²+66x+72
Step-by-step explanation:
Factors are: (x+3)(x+1)(x-4)(x-6)
[(x+3)(x+1)][(x-4)(x-6)]
[x²+3x+x+3][x²-4x-6x+24]
(x²+4x+3)(x²-10x+24)
x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72
f(x) = x⁴-6x³-13x²+66x+72
The lengths of each of the segments connected by the given pairs of points are:
1. AB = 10 units
2. CD = 17 units
3. EF = 3 units
<h3>How to Find the Length of Segments Connected by Two Points?</h3>
To find the length of a segment connected by two coordinate points, the distance formula is applied, which is:
d =
.
1. Find the length of segment AB:
A(5,-3)
B(-3,3)
AB = √[(−3−5)² + (3−(−3))²]
AB = √[(−8)² + (6)²]
AB = √100
AB = 10 units
2. Find the length of segment CD:
C(-2, -7)
D(6, 8)
CD = √[(6−(−2))² + (8−(−7))²]
CD = √(64 + 225)
CD = 17 units
3. Find the length of segment EF:
E(5,6)
F(5,3)
EF = √[(5−5)² + (3−6)²[
EF = √(0 + 9)
EF = √9
EF = 3 units
Learn more about lengths of segments on:
brainly.com/question/24778489
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