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Natali5045456 [20]
3 years ago
6

COURSES GROUPS RESOURCES GRADE REPORT Q OOO try: 913322 4 Honors Chemistry Tests/Quizzes ormulas Reactions Quiz Questic Question

1 (2 points) How many atoms of cadmium are found in a 37.8 g sample of the element? Report your answer to 3 significant digits. X1023 atoms of silicon​
Chemistry
1 answer:
Aleks04 [339]3 years ago
6 0

Answer:

2.02 × 10²³ atoms

Explanation:

Step 1: Calculate the moles corresponding to 37.8 g of cadmium

To convert mass to moles, we need a conversion factor: the molar mass. The molar mass of cadmium is 112.41 g/mol.

37.8 g × 1 mol/112.41 g = 0.336 mol

Step 2: Calculate the number of atoms in 0.336 moles of cadmium

To convert moles to atoms, we need a conversion factor: Avogadro's number. In 1 mole of atoms of cadmium, there are 6.02 × 10²³ atoms of cadmium.

0.336 mol × 6.02 × 10²³ atoms/1 mol = 2.02 × 10²³ atoms

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For each trial, enter the amount of heat gained by the chemical system of ammonium nitrate, qrxn. The specific heat of water is
shtirl [24]
This is how to solve the problem:

First, we need to find the qcalorimeter.
The, you must use the equation:
<span>qcalorimeter = Csp + (delta)T </span>

<span>(delta)T  = is the same as what you used for
</span><span>CSP = you calculated this earlier in lab. "average heat capacity of the calorimeter" </span>

<span>Hope this helps answer your question.</span>
5 0
3 years ago
Is primarily responsible for acid rain in the northeast United States Uranium-238 Answer A: Uranium-238 A Coal Answer B: Coal B
Georgia [21]

Based on the available facts, in the northeast United States, the biggest source of acid rain producing pollutants comes from the burning of coal by power plants to produce electricity.

<h3>What is acid rain?</h3>

Acid rain occurs when gases such as sulfur (iv) oxide and nitrogen oxides which are released from the burning of fossil fuels such as petrol and coal are released into the atmosphere, which then dissolve in rainwater and fall as acid rain.

These gases are known as acid anhydrides because they dissolve in water to produce acids.

In the northeast United States, the biggest source of acid rain producing pollutants comes from the burning of coal by power plants to produce electricity.

Learn more about acid rain at: brainly.com/question/718250

3 0
3 years ago
A 0.568-g sample of fertilizer contained nitrogen as ammonium sulfate, . It was analyzed for nitrogen by heating with sodium hyd
Mariulka [41]

Answer:

6.69%

Explanation:

Given that:

Mass of  the fertilizer = 0.568 g

The mass of HCl used in titration (45.2 mL of 0.192 M)

= 0.192*\frac{45.2}{1000}* \frac{36.5}{1 \ mole}

= 0.313 g HCl

The amount of NaOH used for the titration of excess HCl (42.4 mL of 0.133M)

= \frac{44.3 \ mL * 1.0 \ L}{1000 \ mL} *0.133 \ mole/L

= 0.0058919 mole of NaOH

From the neutralization reaction; number of moles of HCl is equal with the number of moles of NaOH is needed to complete the neutralization process

Thus; amount of HCl neutralized by 0.0058919 mole of NaOH = 0.0058919 × 36.5 g

= 0.2151 g HCl

From above ; the total amount of HCl used = 0.313 g

The total amount that is used for complete neutralization = 0.2151 g

∴ The amount of HCl reacted with NH₃ = (0.313 - 0.2151)g

= 0.0979 g

We all know that 1 mole of NH₃ = 17.0 g , which requires 1 mole of HCl = 36.5 g

Now; the amount of HCl neutralized by 0.0979 HCl = \frac{17}{36.5}*0.0979

= 0.0456 g

Therefore, the mass of nitrogen present in the fertilizer is:

= 0.0456 \ g \ NH_3 * \frac{1  \ mol \ NH_3 }{17.0 \ mol \ of \ NH_3} * \frac{1  \mol \ (NH_4)_2SO_4}{2 \ mol \ NH_3 } * \frac{2 \ mol \ N }{1  \mol \ (NH_4)_2SO_4}* \frac{14.0 g }{1 \ mol \ N}

= 0.038 g

∴ Mass percentage of Nitrogen in the fertilizer = \frac{0.038 \ g}{0.568 \ g} * 100%

= 6.69%

8 0
4 years ago
Read 2 more answers
2. Heliox is a mixture of gases and is used in medicine to help
yaroslaw [1]

Answer:

people with breathing problems such as severe asthma.

Explanation:

Heliox is a medical treatment for patients with difficulty breathing. The mixture generates less resistance than atmospheric air when passing through the airways of the lungs, and thus requires less effort by a patient to breathe in and out of the lungs.

4 0
3 years ago
A mixture of bases can sometimes be the active ingredient in antacid tablets. If 0.4884 g of a mixture of Al(OH)3 and Mg(OH)2 is
Nitella [24]

Answer:

54.7%

Explanation:

The reaction of neutralization will be:

Al(OH)₃ + Mg(OH)₂ + 5HNO₃ → Al(NO₃)₃ + Mg(NO₃)₂ + 5H₂O

The number of moles of HNO₃ added is the concentration multiplied by the volume (17.12 mL = 0.01712 L)

n = 1*0.01712 = 0.01712 mol

For the stoichiometry:

1 mol of Al(OH)₃  ---------- 5 moles of HNO₃

x ----------------------------------0.01712 mol

By a simple direct three rule:

5x = 0.01712

x = 3.424x10⁻³ mol of Al(OH)₃

For the stoichiometry, the number of moles of Mg(OH)₂ will also be 3.424x10⁻³.

The molar masses are:

Al(OH)₃: 27 g/mol of Al + 3*16 g/mol of O + 3*1 g/mol of H = 78 g/mol

Mg(OH)₂: 24 g/mol of Mg + 2*16 g/mol of O + 2*1 g/mol of H = 58 g/mol

The mass is the molar mass multiplied by the number of moles:

Al(OH)₃: 78*3.424x10⁻³ = 0.2671 g

Mg(OH)₂: 58*3.424x10⁻³ = 0.1986 g

The mass % of Al(OH)₃ in the mixture is its mass divides by the mass of the mixture, multiplied by 100%:

(0.2671/0.4884)x100% = 54.7%

5 0
3 years ago
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