10. When a tool mark is found, what is done first?

What items are minerals or contain minerals

NARA [144]

Answer:

computer

Explanation:

copper-wire

electronics-siliver

7 0

4 years ago

Problem 1:

WARRIOR [948]

Answer:

12,302.59 mL

Explanation:

The problem above requires the conversion of the unit of volume, gallon, to milliliter. 

You have to take note of the following values before computing.

1 L is equivalent to 0.264172 gallons

1 L is equivalent to 1,000 ml

Now, we can do the conversion. Let's convert 3.25 gallons to milliliter.

1. 3.25 gallons x $\frac{1 L}{0.264172 gallons}$ = 12.30259 L

2. 12.30259 L x $\frac{1,000 ml}{1 L}$ = 12,302.59 mL

Therefore, 3.25 gallons of distilled water is equivalent to 12,500 mL of distilled water.

8 0

3 years ago

How much heat do you need to raise the temperature of 100g of aluminum from 30 C to 150 C

SVEN [57.7K]

Answer:

Q = 10.8 KJ

Explanation:

Given data:

Mass of Al= 100g

Initial temperature = 30°C

Final temperature = 150°C

Heat required = ?

Solution:

Specific heat of Al = 0.90 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 150°C - 30°C

ΔT = 120°C

Q = 100g×0.90 J/g.°C× 120°C

Q = 10800 J (10800j×1KJ/1000 j)

Q = 10.8 KJ

4 0

3 years ago

Read 2 more answers

How many times more massive is an oxygen atom than a hydrogen atom?

Gala2k [10]

An oxygen atom is 16x more massive than a hydrogen atom.

You can figure this out by comparing the atomic masses of the two elements: oxygen has an atomic mass number of 16, and hydrogen has an atomic mass number of 1. Thus, an oxygen atom is 16 times more massive than a hydrogen atom.

3 0

3 years ago

Read 2 more answers

A mass of 34.05 g of H2O(s) at 273 K is dropped into 185 g of H2O(l) at 310. K in an insulated container at 1 bar of pressure. C

kykrilka [37]

Answer:

The temperature of the system once equilibrium is reached, is 292 Kelvin

Explanation:

Step 1: Data given

Mass of H2O = 34.05 grams

⇒ temperature = 273 K

Mass of H2O at 310 K = 185 grams

Pressure = 1 bar = 0.9869 atm

Step 2: Calculate the final temperature

n(ice)*ΔH(ice fusion) + n(ice)*CP(H2O)(Tfinal- Ti,ice) + n(H20)*CP(H2O)*(Tfinal-Ti,H2O) = 0

Tfinal = [n(ice)*CP(ice)*Ti(ice) + n(H2O)*CP(H2O)*Ti(H20) - n(ice)*ΔH(ice fusion)] / [n(ice)*CP(ice) +n(H2O)*CP(H2O)]

⇒ with n(ice) = moles of ice = 34.05 grams / 18.02 g/mol = 1.890 moles

⇒ with CP(ice) = 75.3 J/K*mol

⇒ with Ti(ice) = the initial temperature of ice = 273 K

⇒ with n(H2O) = the moles of water = 185.0 grams / 18.02 g/mol = 10.27 moles

⇒ with CP(H2O) = CP(ice) = 75.3 J/K*mol

⇒ with Ti(H2O) = the initial temperature of the water = 310 K

⇒ with ΔH(ice, fusion) = 6010 J/mol

Tfinal = [1.890 moles * 75.3 J/K*mol * 273 + 10.27 mol * 75.3 J/K*mol * 310 K - 1.890 moles * 6010 J/mol] / [1.890 moles *75.3J/k*mol + 10.27 mol * 75.3 J/K*mol]

38852.541 + 239732.61 - 11358.9 = 267226.251

Tfinal= 291.8 ≈ 292 Kelvin

The temperature of the system once equilibrium is reached, is 292 Kelvin

8 0

4 years ago